英文:
Golang - retrieve multiple results from MySQL, then display them as JSON
问题
最近，我正在学习Go（Golang）。我正在尝试使用Martini和jwt-go创建一个简单的Web服务。在检索单行数据并将其放入JSON作为响应方面，我没有遇到任何困难。但是，当处理多行数据时，情况就完全不同了。基本上，我参考了这里的被接受的答案。
以下是我的代码片段：
m.Get("/users", func(params martini.Params, r render.Render) {db, err := sql.Open("mysql", "root:@/sirat_v2")if err != nil {panic(err.Error())}defer db.Close()rows, err := db.Query("SELECT user_id, nama FROM `users` WHERE password = ?", "asdfasdf")defer rows.Close()cols, err := rows.Columns()if err != nil {panic(err.Error())}partages := make([]*Partage, 0, 10)var user_id intvar nama stringfor rows.Next() {err = rows.Scan(&user_id, &nama)if err != nil { /* error handling */}partages = append(partages, &Partage{user_id, nama})}})
在尝试构建时，出现了一个错误，说Partage未定义。
英文:
Recently, I'm learning about Go (Golang). I'm trying to make a simple web service using Martini and jwt-go. I didn't find any difficulty in retrieving a single row data and put in JSON as the response. But, when dealing with multiple-rows, it's a whole different story. Basically, I refer to the accepted answer here.
Here is the piece of my code:
m.Get("/users", func(params martini.Params, r render.Render) {db, err := sql.Open("mysql", "root:@/sirat_v2")if err != nil {panic(err.Error())}defer db.Close()rows, err := db.Query("SELECT user_id, nama FROM `users` WHERE password = ?", "asdfasdf")defer rows.Close()cols, err := rows.Columns()if err != nil {panic(err.Error())}partages := make([]*Partage, 0, 10)var user_id intvar nama stringfor rows.Next() {err = rows.Scan(&user_id, &nama)if err != nil { /* error handling */}partages = append(partages, &Partage{user_id, nama})}})
When trying to build, there's an error said that Partage is undefined.
答案1
得分: 2
错误出现是因为您使用结构体Partage创建了一个对象，但您没有声明它。
type Partage struct {user_id stringnama string}
> 但是我如何将结果显示为JSON响应？我尝试了r.JSON(200, partages)，但结果没有显示出来。
在martini中，您可以使用r.JSON()将rows打印为JSON。
m.Get("/users", func(params martini.Params, r render.Render) {// ...r.JSON(200, map[string]interface{}{"data": rows})})
英文:
The error showing up because you use struct Partage to create an object, but you haven't declared it.
type Partage struct {user_id stringnama string}
> But how do I display the result as JSON response? I've tried r.JSON(200, partages) but the results aren't displayed
In martini you can use r.JSON() to print rows as JSON
m.Get("/users", func(params martini.Params, r render.Render) {// ...r.JSON(200, map[string]interface{}{data: rows})})
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