英文:
Adding to an anonymous slice in a type in golang
问题
我想在一个切片上添加一些辅助方法。所以我创建了一个类型 []*MyType。有没有办法向这个 MyTypes 切片添加元素？append 方法无法识别这个切片。
package main
import "fmt"
type MyType struct{
Name string
Something string
}
type MyTypes []*MyType
func NewMyTypes(myTypes ...*MyType)*MyTypes{
var s MyTypes = myTypes
return &s
}
//example of a method I want to be able to add to a slice
func(m MyTypes) Key() string{
var result string
for _,i := range m{
result += i.Name + ":"
}
return result
}
func main() {
mytype1 ,mytype2 := MyType{Name:"Joe", Something: "Foo"}, MyType{Name:"PeggySue", Something: "Bar"}
myTypes:= NewMyTypes(&mytype1,&mytype2)
//cant use it as a slice sadface
//myTypes = append(myTypes,&MyType{Name:"Random", Something: "asdhf"})
fmt.Println(myTypes.Key())
}
我不想将其包装在另一个类型中，并命名参数，尽管我有点这样做。因为 JSON 编组可能会有所不同。
有什么方法可以向 MyTypes 切片添加元素？
我真的希望能够只是向切片添加一个方法，以便它可以实现特定的接口，而不影响编组。有没有其他更好的方法？
谢谢
英文:
I want to add a few helper methods attached onto a slice.
So I created a type which is of []*MyType
Is there any way to add to that slice of MyTypes? append will not recognise the slice.
package main
import "fmt"
type MyType struct{
Name string
Something string
}
type MyTypes []*MyType
func NewMyTypes(myTypes ...*MyType)*MyTypes{
var s MyTypes = myTypes
return &s
}
//example of a method I want to be able to add to a slice
func(m MyTypes) Key() string{
var result string
for _,i := range m{
result += i.Name + ":"
}
return result
}
func main() {
mytype1 ,mytype2 := MyType{Name:"Joe", Something: "Foo"}, MyType{Name:"PeggySue", Something: "Bar"}
myTypes:= NewMyTypes(&mytype1,&mytype2)
//cant use it as a slice sadface
//myTypes = append(myTypes,&MyType{Name:"Random", Something: "asdhf"})
fmt.Println(myTypes.Key())
}
I don't want to wrap it in another type and name the param even though I'm sorta doing it.. Because of json marshalling will probably be different
What would be the way to add to the MyTypes slice?
I really want to just be able to add a method to a slice so it can implement a specific interface and not effect the marshalling.. Is there a different better way?
Thanks
答案1
得分: 2
更新：这个答案曾经包含了两种解决问题的方法：我有点笨拙的方法和DaveC更优雅的方法。这是他更优雅的方法：
package main
import (
"fmt"
"strings"
)
type MyType struct {
Name string
Something string
}
type MyTypes []*MyType
func NewMyTypes(myTypes ...*MyType) MyTypes {
return myTypes
}
//example of a method I want to be able to add to a slice
func (m MyTypes) Names() []string {
names := make([]string, 0, len(m))
for _, v := range m {
names = append(names, v.Name)
}
return names
}
func main() {
mytype1, mytype2 := MyType{Name: "Joe", Something: "Foo"}, MyType{Name: "PeggySue", Something: "Bar"}
myTypes := NewMyTypes(&mytype1, &mytype2)
myTypes = append(myTypes, &MyType{Name: "Random", Something: "asdhf"})
fmt.Println(strings.Join(myTypes.Names(), ":"))
}
Playground: https://play.golang.org/p/FxsUo1vu6L
英文:
Update: This answer once contained two ways to solve the problem: my somewhat clunky way, the DaveC's more elegant way. Here's his more elegant way:
package main
import (
"fmt"
"strings"
)
type MyType struct {
Name string
Something string
}
type MyTypes []*MyType
func NewMyTypes(myTypes ...*MyType) MyTypes {
return myTypes
}
//example of a method I want to be able to add to a slice
func (m MyTypes) Names() []string {
names := make([]string, 0, len(m))
for _, v := range m {
names = append(names, v.Name)
}
return names
}
func main() {
mytype1, mytype2 := MyType{Name: "Joe", Something: "Foo"}, MyType{Name: "PeggySue", Something: "Bar"}
myTypes := NewMyTypes(&mytype1, &mytype2)
myTypes = append(myTypes, &MyType{Name: "Random", Something: "asdhf"})
fmt.Println(strings.Join(myTypes.Names(), ":"))
}
Playground: https://play.golang.org/p/FxsUo1vu6L
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