Dynamic function call in Go

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英文:

Dynamic function call in Go

问题

我正在尝试动态调用返回不同类型的struct的函数。

例如,让我们看一下以下代码。

struct A {
   Name string
   Value  int
}

struct B {
   Name1 string
   Name2 string
   Value   float
}

func doA() (A) {
   // 一些返回A的代码
}

func doB() (B) {
   // 一些返回B的代码
}

我想将函数doAdoB作为参数传递给一个通用函数,该函数将执行该函数并对结果进行JSON编码。就像下面这样:

func Generic(w io.Writer, fn func() (interface {}) {
    result := fn()
    json.NewEncoder(w).Encode(result)
}

但是当我这样做时:

Generic(w, doA)

我得到以下错误:

无法将doA(类型为func()(A))用作类型为func()(interface {})的参数

有没有办法实现这种动态调用?

英文:

I'm trying to dynamically call functions returning different types of struct.

For example, let's take the following code.

struct A {
   Name string
   Value  int
}

struct B {
   Name1 string
   Name2 string
   Value   float
}

func doA() (A) {
   // some code returning A
}

func doB() (B) {
   // some code returning B
}

I would like to pass either the function doA or doB as an argument to a generic function that would execute the function and JSON-encode the result. Like the following:

func Generic(w io.Writer, fn func() (interface {}) {
    result := fn()
    json.NewEncoder(w).Encode(result)
}

But when I do:

Generic(w, doA)

I get the following error:

cannot use doA (type func() (A)) as type func() (interface {})

Is there a way to achieve this dynamic call?

答案1

得分: 15

首先,让我说明一下 func() (interface{})func() interface{} 是相同的意思,所以我将使用更短的形式。

传递类型为 func() interface{} 的函数

你可以编写一个通用函数,接受一个 func() interface{} 类型的参数,只要你传递给它的函数的类型是 func() interface{},就像这样:

type A struct {
    Name  string
    Value int
}

type B struct {
    Name1 string
    Name2 string
    Value float64
}

func doA() interface{} {
    return &A{"Cats", 10}
}

func doB() interface{} {
    return &B{"Cats", "Dogs", 10.0}
}

func Generic(w io.Writer, fn func() interface{}) {
    result := fn()
    json.NewEncoder(w).Encode(result)
}

你可以在实时 playground 中尝试这段代码:

http://play.golang.org/p/JJeww9zNhE

将函数作为类型为 interface{} 的参数传递

如果你想编写返回具体类型值的函数 doAdoB,你可以将所选函数作为类型为 interface{} 的参数传递。然后,你可以使用 reflect 在运行时创建一个 func() interface{}

func Generic(w io.Writer, f interface{}) {
    fnValue := reflect.ValueOf(f)        // 创建一个具体值。
    arguments := []reflect.Value{}       // 创建一个空的参数列表。
    fnResults := fnValue.Call(arguments) // 假设我们有一个函数。调用它。
    result := fnResults[0].Interface()   // 将第一个结果作为 interface{} 获取。
    json.NewEncoder(w).Encode(result)    // 对结果进行 JSON 编码。
}

更简洁的写法:

func Generic(w io.Writer, fn interface{}) {
    result := reflect.ValueOf(fn).Call([]reflect.Value{})[0].Interface()
    json.NewEncoder(w).Encode(result)
}

完整的程序:

package main

import (
    "encoding/json"
    "io"
    "os"
    "reflect"
)

type A struct {
    Name  string
    Value int
}

type B struct {
    Name1 string
    Name2 string
    Value float64
}

func doA() *A {
    return &A{"Cats", 10}
}

func doB() *B {
    return &B{"Cats", "Dogs", 10.0}
}

func Generic(w io.Writer, fn interface{}) {
    result := reflect.ValueOf(fn).Call([]reflect.Value{})[0].Interface()
    json.NewEncoder(w).Encode(result)
}

func main() {
    Generic(os.Stdout, doA)
    Generic(os.Stdout, doB)
}

实时 playground:

http://play.golang.org/p/9M5Gr2HDRN

英文:

First, let me remark that func() (interface{}) means the same thing as func() interface{}, so I'll use the shorter form.

Passing a function of type func() interface{}

You can write a generic function that takes a func() interface{} argument as long as the function that you pass to it has type func() interface{}, like this:

type A struct {
	Name  string
	Value int
}

type B struct {
	Name1 string
	Name2 string
	Value float64
}

func doA() interface{} {
	return &A{"Cats", 10}
}

func doB() interface{} {
	return &B{"Cats", "Dogs", 10.0}
}

func Generic(w io.Writer, fn func() interface{}) {
	result := fn()
	json.NewEncoder(w).Encode(result)
}

You can try out this code in a live playground:

http://play.golang.org/p/JJeww9zNhE

Passing a function as an argument of type interface{}

If you want to write functions doA and doB that return concretely typed values, you can pass the chosen function as an argument of type interface{}. Then you can use the reflect package to make a func() interface{} at run-time:

func Generic(w io.Writer, f interface{}) {
	fnValue := reflect.ValueOf(f)        // Make a concrete value.
	arguments := []reflect.Value{}       // Make an empty argument list.
	fnResults := fnValue.Call(arguments) // Assume we have a function. Call it.
	result := fnResults[0].Interface()   // Get the first result as interface{}.
	json.NewEncoder(w).Encode(result)    // JSON-encode the result.
}

More concisely:

func Generic(w io.Writer, fn interface{}) {
	result := reflect.ValueOf(fn).Call([]reflect.Value{})[0].Interface()
	json.NewEncoder(w).Encode(result)
}

Complete program:

package main

import (
	"encoding/json"
	"io"
	"os"
	"reflect"
)

type A struct {
	Name  string
	Value int
}

type B struct {
	Name1 string
	Name2 string
	Value float64
}

func doA() *A {
	return &A{"Cats", 10}
}

func doB() *B {
	return &B{"Cats", "Dogs", 10.0}
}

func Generic(w io.Writer, fn interface{}) {
	result := reflect.ValueOf(fn).Call([]reflect.Value{})[0].Interface()
	json.NewEncoder(w).Encode(result)
}

func main() {
	Generic(os.Stdout, doA)
	Generic(os.Stdout, doB)
}

Live playground:

http://play.golang.org/p/9M5Gr2HDRN

答案2

得分: 0

你的返回签名与这些函数不同:
fn func() (interface {})func doA() (A)func doB() (B)

你得到了一个编译器错误,因为你将一个具有不同签名的函数传递给了你的 Generic 函数。为了解决这个问题,你可以将你的函数改为返回 interface{}

这是一个示例,我使用匿名结构体并将返回值打印出来,而不是将它们序列化,但对于你的示例同样适用:

package main

import "fmt"

func doA() interface{} {
	return struct {
		Name  string
		Value int
	}{
		"something",
		5,
	}
}

func doB() interface{} {
	return struct {
		Name1 string
		Name2 string
		Value float64
	}{
		"something",
		"or other",
		5.3,
	}
}

func main() {
	fmt.Println("Hello, playground", doA(), doB())
}

在 Go Playground 中尝试一下:http://play.golang.org/p/orrJw2XMW8

英文:

Your return signature is different for these functions:
fn func() (interface {}) vs. func doA() (A) and func doB() (B)

You are getting a compiler error because you are passing a function with a different signature into your Generic function. To address this issue you can change your functions to return interface{}.

This is an example of how to do that, I am using anonymous structs and printing the return value out rather than serializing them but this applies just the same to your example:

package main

import "fmt"

func doA() interface{} {
	return struct {
		Name  string
		Value int
	}{
		"something",
		5,
	}
}

func doB() interface{} {
	return struct {
		Name1 string
		Name2 string
		Value float64
	}{
		"something",
		"or other",
		5.3,
	}
}

func main() {
	fmt.Println("Hello, playground", doA(), doB())
}

Experiment with this in the Go Playground: http://play.golang.org/p/orrJw2XMW8

huangapple
  • 本文由 发表于 2015年9月20日 05:27:15
  • 转载请务必保留本文链接:https://go.coder-hub.com/32673407.html
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