英文:
Trying to convert string to instance variable
问题
我是你的中文翻译助手，以下是翻译好的内容：
我是GO语言的新手。
尝试通过构建真实的Web应用程序来学习GO。
我正在使用revel框架。
这是我的资源路由：
GET /resource/:resource Resource.ReadAllGET /resource/:resource/:id Resource.ReadPOST /resource/:resource Resource.CreatePUT /resource/:resource/:id Resource.UpdateDELETE /resource/:resource/:id Resource.Delete
例如：
GET /resource/users 调用 Resource.ReadAll("users")
这是我的Resource控制器（目前只是一个虚拟操作）：
type Resource struct {*revel.Controller}type User struct {Id intUsername stringPassword string}type Users struct {}func (u Users) All() string {return "All"}func (c Resource) ReadAll(resource string) revel.Result {fmt.Printf("GET %s", resource)model := reflect.New(resource)fmt.Println(model.All())return nil}
我试图通过将resource string转换为对象来获取Users结构体的实例，以调用All函数。
错误信息为：
无法将类型为string的resource用作reflect.Type的参数传递给reflect.New：string未实现reflect.Type（缺少Align方法）
我是GO的新手，请不要评判我 
英文:
I'm new to GO language.
Trying to learn GO by building real web application.
I'm using revel framework.
And here is my resource routes:
GET /resource/:resource Resource.ReadAllGET /resource/:resource/:id Resource.ReadPOST /resource/:resource Resource.CreatePUT /resource/:resource/:id Resource.UpdateDELETE /resource/:resource/:id Resource.Delete
for example:
GET /resource/users calls Resource.ReadAll("users")
And this is my Resource controller (it's just a dummy actions for now):
type Resource struct {*revel.Controller}type User struct {Id intUsername stringPassword string}type Users struct {}func (u Users) All() string {return "All"}func (c Resource) ReadAll(resource string) revel.Result {fmt.Printf("GET %s", resource)model := reflect.New(resource)fmt.Println(model.All())return nil}
I'm trying get instance of Users struct by converting resource string to object to call All function.<br/>
and the error:
> cannot use resource (type string) as type reflect.Type in argument to
> reflect.New: string does not implement reflect.Type (missing Align
> method)
I'm new to GO please don't judge me
答案1
得分: 3
你的问题在这里：
model := reflect.New(resource)
你不能用这种方式从字符串实例化一个类型。你需要在那里使用switch，并根据模型执行相应的操作：
switch resource {case "users":model := &Users{}fmt.Println(model.All())case "posts":// ...}
或者正确使用reflect。类似这样：
var types = map[string]reflect.Type{"users": reflect.TypeOf(Users{}) // 或者 &Users{}.}// ...model := reflect.New(types[resource])res := model.MethodByName("All").Call(nil)fmt.Println(res)
英文:
Your problem is here:
model := reflect.New(resource)
You can't instantiate a type from a string that way. You need to either use a switch there and do stuff depending on the model:
switch resource {case "users":model := &Users{}fmt.Println(model.All())case "posts":// ...}
Or use reflect correctly. Something like:
var types = map[string]reflect.Type{"users": reflect.TypeOf(Users{}) // Or &Users{}.}// ...model := reflect.New(types[resource])res := model.MethodByName("All").Call(nil)fmt.Println(res)
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