英文:
Can you explain parameters between func keyword and function name?
问题
我是你的中文翻译助手，以下是翻译好的内容：
我对这门语言还不熟悉，到目前为止，我所读的内容并没有解释这里发生了什么。
我在查看JSON解码。
这是该包中的一个函数：
func (dec *Decoder) Decode(v interface{}) error
这里也有类似的表示法：
func (dec *Decoder) Buffered() io.Reader
这些函数如何访问(dec *Decoder)？考虑到第二个函数没有参数，我猜想这不是必须直接在函数调用中传递的，而是类似的东西？
英文:
I'm new to the language and so far what I have read doesn't explain what is happening here.
I was looking at JSON decoding.
Here is a function in the package:
func (dec *Decoder) Decode(v interface{}) error
There is similar notation here:
func (dec *Decoder) Buffered() io.Reader
How do these functions access the (dec *Decoder)? Given that the second function has no parameters, I am guessing this is not something that must be passed directly in the function call but something similar?
答案1
得分: 4
这两个函数是方法，因为它们与接收器相关联。在每个方法声明中，(dec *Decoder)描述了接收器。如果你有一个名为decoder的*Decoder，你可以像这样调用它的Buffered方法：
reader := decoder.Buffered()
请参考Go教程中的这个主题。
英文:
These two functions are methods because they are associated with receivers. In each method declaration, (dec *Decoder) describes the receiver. If you have a *Decoder called decoder, you call Buffered on it like this:
reader := decoder.Buffered()
Take a look at the the Go tutorial lesson on this topic.
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