英文:
multilevel slices with string indexes
问题
我有一个代码看起来像这样：
var c [][]string
c = append(c, d)
c = append(c, l)
假设d和l都是[]string。这个代码是有效的，但它返回的结果是这样的：
[["0241025570","0241025571","1102182000"],["0241025570","0241025571","1102182000"]]
如何将其结构化为这样的形式：
["d": ["0241025570","0241025571","1102182000"], "l":["0241025570","0241025571","1102182000"]]
英文:
I have a code that looks like this:
var c [][]string
c = append(c, d)
c = append(c, l)
Assuming that both d and l are []strings. This works, however it would return something like this:
[["0241025570","0241025571","1102182000"],["0241025570","0241025571","1102182000"]]
How would it be possible to structure it to look like this:
["d": ["0241025570","0241025571","1102182000"], "l":["0241025570","0241025571","1102182000"]]
答案1
得分: 4
你想要的不再是一个切片，而是一个切片的映射。你可以使用以下代码来获得所需的结果：
c := make(map[string][]string)
c["d"] = d
c["l"] = l
根据你的使用情况，你可能希望对 d 和 l 进行复制，而不是直接在映射中使用它们：
c := make(map[string][]string)
c["d"] = make([]string, len(d))
c["l"] = make([]string, len(l))
copy(c["d"], d)
copy(c["l"], l)
英文:
What you would like to have would no longer be a slice, but a map of slices. You can get the desired results using the following code:
c := make(map[string][]string)
c["d"] = d
c["l"] = l
Depending on your usage, you may want to make copies of d and l, instead of using them directly in the map:
c := make(map[string][]string)
c["d"] = make([]string, len(d))
c["l"] = make([]string, len(l))
copy(c["d"], d)
copy(c["l"], l)
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