英文:
How do I parse URLs in the format of /id/123 not ?foo=bar
问题
我正在尝试解析一个像这样的URL：
我已经阅读了net/url文档，但似乎它只能解析像这样的字符串：
http://example.com/blah?id=123
我该如何解析ID，以便在第一个示例中得到id的值？
这不是我自己的路由，而是从一个openid请求返回的http字符串。
英文:
I'm trying to parse an URL like:
I've read through the net/url docs but it seems like it only parses strings like
http://example.com/blah?id=123
How can I parse the ID so I end up with the value of the id in the first example?
This is not one of my own routes but a http string returned from an openid request.
答案1
得分: 16
在你的示例中，/id/123是一个路径，你可以使用路径模块的Base函数来获取"123"部分。
package mainimport ("fmt""path")func main() {fmt.Println(path.Base("/id/123"))}
为了方便参考，这是路径模块的文档：http://golang.org/pkg/path/#example_Base
英文:
In your example /id/123 is a path and you can get the "123" part by using Base from the path module.
package mainimport ("fmt""path")func main() {fmt.Println(path.Base("/id/123"))}
For easy reference, here's the docs on the path module. http://golang.org/pkg/path/#example_Base
答案2
得分: 8
你可以尝试使用以下正则表达式：
import "regexp"re, _ := regexp.Compile("/id/(.*)")values := re.FindStringSubmatch(path)if len(values) > 0 {fmt.Println("ID : ", values[1])}
这段代码使用了正则表达式来匹配路径中的ID。如果匹配成功，它会打印出ID的值。
英文:
You can try using regular expression as follow:
import "regexp"re, _ := regexp.Compile("/id/(.*)")values := re.FindStringSubmatch(path)if len(values) > 0 {fmt.Println("ID : ", values[1])}
答案3
得分: 3
以下是翻译好的内容：
这是一个适用于与您的URL具有相同结构的简单解决方案（您可以根据其他结构进行改进）。
package mainimport ("fmt""net/url")var path = "http://localhost:8080/id/123"func getFirstParam(path string) (ps string) {// 忽略第一个'/'，并在第二个'/'出现时获取其后的内容作为参数for i := 1; i < len(path); i++ {if path[i] == '/' {ps = path[i+1:]}}return}func main() {u, _ := url.Parse(path)fmt.Println(u.Path) // -> "/id/123"fmt.Println(getFirstParam(u.Path)) // -> "123"}
或者，如@gollipher建议的那样，使用path包：
import "path"func main() {u, _ := url.Parse(path)ps := path.Base(u.Path)}
使用这种方法比正则表达式更快，前提是您事先知道所获取的URL的结构。
英文:
Here is a simple solution that works for URLs with the same structure as yours (you can improve to suit those with other structures)
package mainimport ("fmt""net/url")var path = "http://localhost:8080/id/123"func getFirstParam(path string) (ps string) {// ignore first '/' and when it hits the second '/'// get whatever is after it as a parameterfor i := 1; i < len(path); i++ {if path[i] == '/' {ps = path[i+1:]}}return}func main() {u, _ := url.Parse(path)fmt.Println(u.Path) // -> "/id/123"fmt.Println(getFirstParam(u.Path)) // -> "123"}
Or, as @gollipher suggested, use the path package
import "path"func main() {u, _ := url.Parse(path)ps := path.Base(u.Path)}
With this method it's faster than regex, provided you know before hand the structure of the URL you are getting.
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