英文:
How do I turn a bool into an int?
问题
在Go语言中，没有三元运算符（ternary operator）。但是你可以使用if-else语句来实现相同的功能。你可以这样重写你的代码：
func g(arg bool) int {if arg {return 3} else {return 45}}
这样，如果arg为true，则返回3；如果arg为false，则返回45。
英文:
I'm used to C/Java, where I could use ?: as in:
func g(arg bool) int {return mybool ? 3 : 45;}
Since Go does not have a ternary operator,
how do I do that in go?
答案1
得分: 14
你可以使用以下代码：
func g(mybool bool) int {if mybool {return 3} else {return 45}}
我为你生成了一个playground，供你测试使用。
正如Atomic_alarm和FAQ所指出的，“Go语言中没有三元形式”。
作为对你“如何将bool转换为int”的更一般性回答，程序员通常期望true为1，false为0，但是Go语言没有直接的bool到int的转换方式，因此int(true)或int(false)是无法工作的。
你可以像VP8中那样创建一个简单的函数：
func btou(b bool) uint8 {if b {return 1}return 0}
英文:
You can use the following:
func g(mybool bool) int {if mybool {return 3} else {return 45}}
And I generated a playground for you to test.
As pointed to by Atomic_alarm and the FAQ "There is no ternary form in Go."
As a more general answer to your question of "how to turn a bool into a int" programmers would generally expect true to be 1 and false to be 0, but go doesn't have a direct conversion between bool and int such that int(true) or int(false) will work.
You can create the trivial function in this case as they did in VP8:
func btou(b bool) uint8 {if b {return 1}return 0}
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论