如何清理neoism go-lang的返回类型？

huangapple
go评论130阅读模式
英文:

How can I clean up this return type for neoism go-lang?

问题

我正在尝试使用neoism创建的这个模型现在正在工作，但我无法弄清楚如何使返回类型更短或更清晰。

可能有一种方法可以将这个：
[]struct { UserId string "json:\"account.UserId\""; FirstName string "json:\"account.firstName\""; LastName string "json:\"account.lastName\"" }

变成：
[]Account 或其他什么东西

以下是要翻译的代码：

  1. package models
  3. import (
  4.   "errors"
  5.   "strconv"
  6.   "time"
  8.   "github.com/jmcvetta/neoism"
  9. )
  11. var (
  12.   Accounts map[string]*Account
  13. )
  15. var (
  16.   db *neoism.Database
  17. )
  19. func panicErr(err error) {
  20.   if err != nil {
  21.     panic(err)
  22.   }
  23. }
  25. type Account struct {
  26.   UserId     string `json:"account.UserId"`
  27.   FirstName  string `json:"account.firstName"`
  28.   LastName   string `json:"account.lastName"`
  29. }
  31. func init() {
  32.   var err error
  33.   db, err = neoism.Connect("http://neo4j:password@localhost:7474/db/data")
  34.   if err != nil {
  35.     panic(err)
  36.   }
  37. }
  39. func GetAccounts() []struct {
  40.   UserId     string `json:"account.UserId"`
  41.   FirstName  string `json:"account.firstName"`
  42.   LastName   string `json:"account.lastName"`
  43. } {
  44.   stmt := `
  45.     MATCH (account:Account) RETURN account.UserId, account.firstName, account.lastName
  46.   `
  48.   res := []struct {
  49.     UserId     string `json:"account.UserId"`
  50.     FirstName  string `json:"account.firstName"`
  51.     LastName   string `json:"account.lastName"`
  52.   }{}
  54.   cq := neoism.CypherQuery{
  55.     Statement:  stmt,
  56.     Result:     &res,
  57.   }
  59.   err := db.Cypher(&cq)
  60.   panicErr(err)
  62.   return res
  63. }

以下是另一个副本：
http://play.golang.org/p/14gzc0a_89

我是Go的新手，我正在根据这些neoism的示例进行开发：
https://gist.github.com/verdverm/b43444063995a7f5b913

有很多示例，但verdverm只是输出而不是返回。

我还有一个控制器，我想在其中输出JSON。

  1. package controllers
  3. import (
  4.   "github.com/astaxie/beego"
  5.   "social/models"
  6. )
  8. type AccountsController struct {
  9.   beego.Controller
  10. }
  12. func (c *AccountsController) Get() {
  13.   c.Data["json"] = models.GetAccounts()
  14.   c.ServeJson()
  15. }

希望对Go的新手有所帮助！

英文:

This model I am trying to make with neoism is working now but I can't figure out how to make the return type shorter and or cleaner looking.
There must be a way to make this:
[]struct { UserId string "json:\"account.UserId\""; FirstName string "json:\"account.firstName\""; LastName string "json:\"account.lastName\"" }

Into:
[]Account or something

  1. package models
  3. import (
  4.   "errors"
  5.   "strconv"
  6.   "time"
  7.   // "fmt"
  9.   "github.com/jmcvetta/neoism"
  10. )
  12. var (
  13.   Accounts map[string]*Account
  14. )
  16. var (
  17.   db *neoism.Database
  18. )
  20. func panicErr(err error) {
  21.   if err != nil {
  22.     panic(err)
  23.   }
  24. }
  26. type Account struct {
  27.   UserId   string `json:"account.UserId"`
  28.   FirstName     string `json:"account.firstName"`
  29.   LastName      string `json:"account.lastName"`
  30. }
  32. func init() {
  33.   var err error
  34.   db, err = neoism.Connect("http://neo4j:password@localhost:7474/db/data")
  35.   if err != nil {
  36.     panic(err)
  37.   }
  38. }
  40. // map[lastName:PATRUS UserId:7f7014f9-bd59-4739-8e1b-5aebfa00f4c5 firstName:LARISSA]
  42. func GetAccounts() []struct { UserId string "json:\"account.UserId\""; FirstName string "json:\"account.firstName\""; LastName string "json:\"account.lastName\"" } {
  43.   stmt := `
  44.     MATCH (account:Account) RETURN account.UserId, account.firstName, account.lastName
  45.   `
  47.   res := []struct {
  48.     UserId string `json:"account.UserId"`
  49.     FirstName  string `json:"account.firstName"`
  50.     LastName  string `json:"account.lastName"`
  51.   }{}
  53.   // construct query
  54.   cq := neoism.CypherQuery{
  55.     Statement:  stmt,
  56.     Result:     &res,
  57.   }
  59.   // execute query
  60.   err := db.Cypher(&cq)
  61.   panicErr(err)
  63.   return res
  64. }

Here is another copy:
http://play.golang.org/p/14gzc0a_89

I am new to go and I am going off of these examples for neoism:
https://gist.github.com/verdverm/b43444063995a7f5b913

There are many examples, but verdverm is always just outputting and not returning.

I have a controller as well where I would like to output the json.

  1. package controllers
  3. import (
  4.   "github.com/astaxie/beego"
  5.   "social/models"
  6. )
  8. type AccountsController struct {
  9.   beego.Controller
  10. }
  12. func (c *AccountsController) Get() {
  13.   c.Data["json"] = models.GetAccounts()
  14.   // c.Data["json"] = "hello world"
  15.   c.ServeJson()
  16. }

Thanks for any help/tips for go newbie!

答案1

得分: 0

GetAccounts()函数能够返回一个账户指针的数组吗？

func GetAccounts() []*Account {}

英文:

Can getAccounts return an array of account pointers?

func GetAccounts() []*Account {}

答案2

得分: 0

包模型

导入 (
"错误"
"strconv"
"时间"
// "fmt"

"github.com/jmcvetta/neoism"
)

var (
账户映射[string]*账户
)

var (
数据库 *neoism.数据库
)

func 报错(err 错误) {
如果 err != nil {
报错(err)
}
}

类型 账户 结构体 {
用户ID 字符串 json:"account.UserId"
名字 字符串 json:"account.firstName"
姓氏 字符串 json:"account.lastName"
}

初始化() {
var err 错误
数据库, err = neoism.连接("http://neo4j:password@localhost:7474/db/data")
如果 err != nil {
报错(err)
}
}

// map[lastName:PATRUS UserId:7f7014f9-bd59-4739-8e1b-5aebfa00f4c5 firstName:LARISSA]

获取账户() []账户 {
语句 := MATCH (account:Account) RETURN account.UserId, account.firstName, account.lastName

var 账户们 []账户

// 构建查询
cq := neoism.CypherQuery{
语句: 语句,
结果: &账户们,
}

// 执行查询
错误 := 数据库.Cypher(&cq)
报错(错误)

返回 账户们
}

在函数之前使用上面的账户结构体，然后在内部创建一个变量，并使用指针将其用于neoism数据库的响应。

英文: 
  1. package models
  3. import (
  4.   "errors"
  5.   "strconv"
  6.   "time"
  7.   // "fmt"
  9.   "github.com/jmcvetta/neoism"
  10. )
  12. var (
  13.   Accounts map[string]*Account
  14. )
  16. var (
  17.   db *neoism.Database
  18. )
  20. func panicErr(err error) {
  21.   if err != nil {
  22.     panic(err)
  23.   }
  24. }
  26. type Account struct {
  27.   UserId   string `json:"account.UserId"`
  28.   FirstName     string `json:"account.firstName"`
  29.   LastName      string `json:"account.lastName"`
  30. }
  32. func init() {
  33.   var err error
  34.   db, err = neoism.Connect("http://neo4j:password@localhost:7474/db/data")
  35.   if err != nil {
  36.     panic(err)
  37.   }
  38. }
  40. // map[lastName:PATRUS UserId:7f7014f9-bd59-4739-8e1b-5aebfa00f4c5 firstName:LARISSA]
  42. func GetAccounts() []Account {
  43.   stmt := `
  44.     MATCH (account:Account) RETURN account.UserId, account.firstName, account.lastName
  45.   `
  47.   var accounts []Account
  49.   // construct query
  50.   cq := neoism.CypherQuery{
  51.     Statement:  stmt,
  52.     Result:     &accounts,
  53.   }
  55.   // execute query
  56.   err := db.Cypher(&cq)
  57.   panicErr(err)
  59.   return accounts
  60. }

need to use the Account struct above the function and then make a variable inside and use pointer to var for the response of neoism db.

huangapple
  • 本文由 发表于 2015年7月15日 09:10:11
  • 转载请务必保留本文链接：https://go.coder-hub.com/31419861.html
  • go
  • json
  • neo4j
  • neoism
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