英文:
Case insensitive string comparison in Go
问题
如何以不区分大小写的方式比较字符串？
例如，"Go" 和 "go" 应该被视为相等。
英文:
How do I compare strings in a case insensitive manner?
For example, "Go" and "go" should be considered equal.
答案1
得分: 109
https://golang.org/pkg/strings/#EqualFold 是你要找的函数。它的使用方法如下（来自链接文档的示例）：
package main
import (
"fmt"
"strings"
)
func main() {
fmt.Println(strings.EqualFold("Go", "go"))
}
英文:
https://golang.org/pkg/strings/#EqualFold is the function you are looking for. It is used like this (example from the linked documentation):
package main
import (
"fmt"
"strings"
)
func main() {
fmt.Println(strings.EqualFold("Go", "go"))
}
答案2
得分: 0
有一个替代strings.EqualFold的方法，叫做bytes.EqualFold，它的工作方式相同。
package main
import (
"bytes"
"fmt"
)
func main() {
fmt.Println(bytes.EqualFold([]byte("Go"), []byte("go")))
}
https://golang.org/pkg/bytes/#EqualFold
英文:
There is alternative to strings.EqualFold, there is bytes.EqualFold which work in same way
package main
import (
"bytes"
"fmt"
)
func main() {
fmt.Println(bytes.EqualFold([]byte("Go"), []byte("go")))
}
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