英文:
json.Marshal map to JSON array
问题
当我尝试序列化一个map时，json.Marshal返回：
{"Map Key":"Map Value"}...
这是正常的行为。但是我可以将其序列化为：
{"Map":[{"Name":"Map Key","Date":"Map Value"},{"Name":"Map Key2","Date":"Map Value2"}]}
英文:
When i try Marshal a map, json.Marshal return:
{"Map Key":"Map Value"}...
This is normal behavior. But i can marshal this to:
{"Map":[{"Name":"Map Key","Date":"Map Value"},{"Name":"Map Key2","Date":"Map Value2"}]}
答案1
得分: 2
你可以定义一个自定义的json.Marshaler接口来实现这个功能，例如：
type mapInfo struct {
Name string `json:"name"`
Date string `json:"date"`
}
type CustomMap map[string]string
func (cm CustomMap) MarshalJSON() ([]byte, error) {
// 如果你想要优化，可以使用bytes.Buffer并自己写入字符串。
var out struct {
Map []mapInfo `json:"map"`
}
for k, v := range cm {
out.Map = append(out.Map, mapInfo{k, v})
}
return json.Marshal(out)
}
func (cm CustomMap) UnmarshalJSON(b []byte) (err error) {
var out struct {
Map []mapInfo `json:"map"`
}
if err = json.Unmarshal(b, &out); err != nil {
return
}
for _, v := range out.Map {
cm[v.Name] = v.Date
}
return
}
[kbd]playground/kbd
英文:
You can define a custom json.Marshaler interface to do that, for example:
type mapInfo struct {
Name string `json:"name"`
Date string `json:"date"`
}
type CustomMap map[string]string
func (cm CustomMap) MarshalJSON() ([]byte, error) {
// if you want to optimize you can use a bytes.Buffer and write the strings out yourself.
var out struct {
Map []mapInfo `json:"map"`
}
for k, v := range cm {
out.Map = append(out.Map, mapInfo{k, v})
}
return json.Marshal(out)
}
func (cm CustomMap) UnmarshalJSON(b []byte) (err error) {
var out struct {
Map []mapInfo `json:"map"`
}
if err = json.Unmarshal(b, &out); err != nil {
return
}
for _, v := range out.Map {
cm[v.Name] = v.Date
}
return
}
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