英文:
How can I store types in go maps for initialisation at a later stage
问题
我正在尝试实现一个工厂函数,该函数将返回满足接口X
合约的多个结构体之一的实例。
m := make(map[string] ?)
func init () {
m["a"] = ?
m["b"] = ?
}
type X interface {
y()
}
type A struct {}
func (a *A) y() {}
type B struct {}
func (b *B) y() {}
func factory(name string) X {
return &m[name]{}
}
上面的代码只是我尝试实现的一个简化示例,我想知道是否有可能实现这个目标,或者是否有其他解决这种需求的Go语言惯用法我没有注意到。
英文:
I'm trying to implement a factory function that will return an instance of one of many structs that fulfil the contract of an interface X
.
m := make(map[string] ?)
func init () {
m["a"] = ?
m["b"] = ?
}
type X interface {
y()
}
type A struct {}
func (a * A) y () {}
type B struct {}
func (b * B) y () {}
function factory(name string) X {
return &m[name]{}
}
The code above is just a simplified demonstration of what I'm trying to achieve - looking for pointers for whether this is possible, or if there is a different go idiom to solve this kind of requirement that I'm missing.
答案1
得分: 1
你可以使用map[string]X
,其中X是接口(可以引用符合X合同的任何对象的值或指针)
或者是否有其他解决这种要求的go习惯用法我没有注意到?
你还可以使用反射(如“实例化新类型”)来实现工厂。
reflect.New(yourtype).Elem().Interface()
你可以在“有没有办法从字符串创建结构体实例?”中看到一个工厂示例。
对于工厂方法(每次返回一个新实例的方法),更快的方法是使用switch(如此示例中所示):
// 根据WidgetType创建一个新的Widget接口,并设置WidgetInfo
func New(wt WidgetType, wi WidgetInfo) Widget_iface {
switch wt {
case Widget_A:
return newWidgetA(wi)
case Widget_B:
return newWidgetB(wi)
}
return nil
}
英文:
You can use map[string]X
, with X the interface (which can reference a value or a pointer of any object respecting X contract)
> or if there is a different go idiom to solve this kind of requirement that I'm missing?
You can also use reflection (as in "Instance new Type") to implement your factory.
reflect.New(yourtype).Elem().Interface()
You can see a factory example in "is there a way to create an instance of a struct from a string?".
The quicker approach for a factory method (returning a new instance each time) is using a switch (like in this example):
// Create a new Widget interface based on WidgetType and set WidgetInfo
func New(wt WidgetType, wi WidgetInfo) Widget_iface {
switch wt {
case Widget_A:
return newWidgetA(wi)
case Widget_B:
return newWidgetB(wi)
}
return nil
}
答案2
得分: 1
如果您有一个简单的值类型,那么可以像@VonC所说的那样,只需使用map[string]X
并返回示例值的副本。
对于其他任何情况,我建议使用一个创建函数的映射,而不是使用反射。就像image
包中的image.RegisterFormat
一样。
例如(playground):
package main
import "fmt"
type X interface {
y()
}
type newXFunc func() X
// 这里只有一个映射变量和两个函数,但是
// 这也可以是一个具有两个方法的类型。
var m = map[string]newXFunc{}
func register(name string, fn newXFunc) {
m[name] = fn
}
func factory(name string) X {
return m[name]()
}
func init() {
// 如果register是公开的,那么这些
// 调用可以在实现A和B的其他包中。
register("a", NewA)
// 对于那些没有/不需要
// 自己独立的“new”函数的简单事物。
register("b", func() X { return B{} })
}
type A struct{}
func (a *A) y() {}
func NewA() X { return &A{} }
type B struct{}
func (b B) y() {}
func main() {
a1 := factory("a")
b1 := factory("b")
fmt.Printf("%T\n", a1)
fmt.Printf("%T\n", b1)
}
英文:
If you have a simple value type then as @VonC said, you can just use map[string]X
and return a copy of the exemplar value.
For anything else, instead of using reflection, I'd just use a map of creation functions. Like what the image
package does with
image.RegisterFormat
.
E.g. (playground):
package main
import "fmt"
type X interface {
y()
}
type newXFunc func() X
// Here just a map variable and two functions, but
// this could be a type with two methods instead.
var m = map[string]newXFunc{}
func register(name string, fn newXFunc) {
m[name] = fn
}
func factory(name string) X {
return m[name]()
}
func init() {
// If register is exported than these
// calls can be in other packages that
// implement A and B.
register("a", NewA)
// For simple things that don't have/need
// their own stand-alone "new" function.
register("b", func() X { return B{} })
}
type A struct{}
func (a *A) y() {}
func NewA() X { return &A{} }
type B struct{}
func (b B) y() {}
func main() {
a1 := factory("a")
b1 := factory("b")
fmt.Printf("%T\n", a1)
fmt.Printf("%T\n", b1)
}
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