英文:
What is the equivalent for bigint.pow(a) in Go?
问题
在我的使用案例中，我想知道以下Java代码在Go中如何实现：
import (
"fmt"
"math/big"
)
func main() {
base := big.NewInt(16)
exponent := big.NewInt(1)
a := new(big.Int).Exp(base, exponent, nil)
fmt.Println(a) // 16
}
我可以导入math/big包并创建大整数，但无法使用Go中的Pow()函数。在Go的文档中也找不到该函数。
我需要为bigint实现自己的Pow()版本吗？有人可以帮助我吗？
英文:
In my use case, I would like to know how the following Java code would be implemented in Go
BigInteger base = new BigInteger("16");
int exponent = 1;
BigInteger a = base.pow(exponent); //16^1 = 16
I am able to import the math/big package and create big integers, but not able to do Pow() function in Go. Also I don't find the function in the Go doc.
Do I have to implement my own version of Pow() for bigint? Could anyone help me on this?
答案1
得分: 29
使用Exp函数，将m设置为nil。
var i, e = big.NewInt(16), big.NewInt(2)
i.Exp(i, e, nil)
fmt.Println(i) // 输出 256
Playground: http://play.golang.org/p/0QFbNHEsn5
英文:
Use Exp with m set to nil.
var i, e = big.NewInt(16), big.NewInt(2)
i.Exp(i, e, nil)
fmt.Println(i) // Prints 256
Playground: http://play.golang.org/p/0QFbNHEsn5
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