regexp get matches by group

I want to parse a string and get the substring inside two quotes

#subject

query="tag1 tag2"

#pattern

query="([a-z ]*)"

#result

tag1 tag2

#code

package main

import (
  "fmt"
  "regexp"
)

var re = regexp.MustCompile(`query="([a-z ]*)"`)

func main() {
  match  := re.FindStringSubmatch(`query="tag1 tag2"`)
  result := make(map[string]string)
  for i, name := range re.SubexpNames() {
     result[name] = match[i]
  }
  fmt.Printf("by name: %v\n", result)
}

http://play.golang.org/p/voKpOlcc8J

#update

string

query="tag1 tag2 tag3" foo="wee"

matches
tag1 tag2 tag3

package main

import "fmt"
import "regexp"

func main() {
	var str string = `query="tag1 tag2 tag3" foo="wee"`
	re := regexp.MustCompile(`query="(([a-z0-9]+) ?)*"`)
	match := re.FindStringSubmatch(str)
	if len(match) == 0 {
		fmt.Print("no matches")
	} else {
		result := make(map[string]string)
		for i, name := range re.SubexpNames(){
			result[name] = match[i]
		}
		fmt.Print(result)
	}
}

http://play.golang.org/p/8vieH4eDd1

You can extract the whole tag string and then Split() it.

package main

import (
	"fmt"
	"regexp"
	"strings"
)

func main() {
	var str string = `query="tag1 tag2 tag3" foo="wee"`
	re := regexp.MustCompile(`query="(.+?)"`)
	match := re.FindStringSubmatch(str)

	if len(match) == 2 {
		fmt.Println(strings.Split(match[1], " "))
	}
}

Output: [tag1 tag2 tag3]

First off, the pattern will not match the digits. You might want to change it to:

var re = regexp.MustCompile(`query="(.*)"`)

Then, in order to get the substring, you can just use FindStringSubmatch:

match := re.FindStringSubmatch(`query="tag1 tag2"`)
if len(match) == 2 {
	fmt.Printf("Found: [%s]\n", match[1])
} else {
	fmt.Println("No match found", match)
}

Output:

> Found: [tag1 tag2]

Then, in order to split the string into seperate tags, I recommend using strings.Split

The regexp does not accept digits, s/[a-z ]/[a-z0-9 ]/

http://play.golang.org/p/ov_zoxBenV