英文:
Problems with Mutex Locking in Go
问题
除了互斥锁之外，一切都运行得很好。在我锁定和解锁之后，它不会执行任何操作。我是否忽略了一些明显的东西？
除此之外，在解锁之后，我想在这个函数内部运行一个函数。我尝试过像调用普通函数一样调用它（timer()），甚至是（go timer()）。
func shield(state *State){
for s := range state.ToggleShield { //run if data on channel
if s == true { //if data on channel is true
fmt.Println("Opening the shields This is uninteruptable. Please wait...")
state.VariableMutex.Lock()
state.Finished = false //disable other commands
state.VariableMutex.Unlock()
fmt.Println("Move!!")
ticker := time.Tick(time.Second)
for i := 10; i >= 0; i-- {
<-ticker
fmt.Printf("\rOn 10/%d", i)
}
}
}
}
英文:
Everything works great apart from the mutex. After I lock and unlock, it won't do anything. Is there something obvious I'm missing?
On top of this, after unlocking, I want to run a function inside this function. I've tried just calling it as a regular function (timer()) and even (go timer()).
func shield(state *State){
for s := range state.ToggleShield { //run if data on channel
if s == true { //if data on channel is true
fmt.Println("Opening the shields This is uninteruptable. Please wait...")
state.VariableMutex.Lock()
state.Finished = false //disable other commands
state.VariableMutex.Unlock()
fmt.Println("Move!!")
ticker := time.Tick(time.Second)
for i := 10; i >= 0; i-- {
<-ticker
fmt.Printf("\rOn 10/%d", i)
}
}
}
}
答案1
得分: 4
《Go编程语言规范》
Go语言中的"go"语句可以将一个函数调用作为独立的并发线程或goroutine在同一地址空间中启动执行。
在调用goroutine时，函数值和参数会像通常一样在调用的goroutine中进行评估，但与常规调用不同，程序的执行不会等待被调用的函数完成。相反，该函数会在一个新的goroutine中独立开始执行。当函数终止时，它的goroutine也会终止。
你的程序似乎没有适当的机制来等待goroutine完成："程序的执行不会等待被调用的函数完成"。为了证明这一点，在你的程序的main函数末尾，我插入了一个简单的等待机制：
// 等待一段时间，以便给goroutine完成的机会
time.Sleep(5 * time.Second)
程序：https://play.golang.org/p/ODdEihip4m
输出：
Toggling Shield
Opening the shields This is uninteruptable. Please wait...
Move!!
On 10/10
On 10/9
On 10/8
On 10/7
On 10/6
程序已退出。
英文:
> The Go Programming Language Specification
>
> Go statements
>
> A "go" statement starts the execution of a function call as an
> independent concurrent thread of control, or goroutine, within the
> same address space.
>
> The function value and parameters are evaluated as usual in the
> calling goroutine, but unlike with a regular call, program execution
> does not wait for the invoked function to complete. Instead, the
> function begins executing independently in a new goroutine. When the
> function terminates, its goroutine also terminates.
Your program does not appear to have proper mechanisms to wait until your goroutines complete: "program execution does not wait for the invoked function to complete." To demonstrate this, I inserted a crude wait mechanism at the end of your program main function:
// wait for a while to give goroutines a chance to complete
time.Sleep(5 * time.Second)
Program: https://play.golang.org/p/ODdEihip4m
Output:
Toggling Shield
Opening the shields This is uninteruptable. Please wait...
Move!!
On 10/10
On 10/9
On 10/8
On 10/7
On 10/6
Program exited.
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