英文:
Extracting information from go-github Gist type
问题
我已经开始学习Go语言,到目前为止我发现它非常有趣。为了提高自己的语言水平,我决定使用go-github在Go中编写一个Gister。
我已经能够使用访问令牌获取所有的Gists,并且能够按如下方式打印出来:
package main
import "fmt"
import "github.com/google/go-github/github"
import "code.google.com/p/goauth2/oauth"
func main() {
t := &oauth.Transport{
Token: &oauth.Token{AccessToken: "secretaccesstokenhere"},
}
client := github.NewClient(t.Client())
gists, _, err := client.Gists.List("", nil)
if err != nil {
fmt.Println(err)
} else {
for _, g := range gists {
fmt.Printf("%v\n\n", g.Files)
}
}
}
我得到以下输出:
map[TODO.md:github.GistFile{Size:166, Filename:"TODO.md", RawURL:"somerawurlhere"}]
map[fourcore.c:github.GistFile{Size:309, Filename:"fourcore.c", RawURL:"somerawurlhere"}]
map[coretest.cpp:github.GistFile{Size:160, Filename:"coretest.cpp", RawURL:"somerawurlhere"}]
我想要打印的是"ID / 文件名"。我知道我需要从Gist类型中提取ID,从上面的map中提取文件名,但是我找不到方法来实现。我该如何做到这一点?非常感谢您的帮助。
附注:这里是描述Gist类型的文档。
英文:
I have started learning Go and I find it quite interesting so far. As an assignment for myself to get get better at the language, I decided to write a Gister in Go using go-github.
I have been able to get all my Gists using an access token and I am able to print as follows:
package main
import "fmt"
import "github.com/google/go-github/github"
import "code.google.com/p/goauth2/oauth"
func main() {
t := &oauth.Transport{
Token: &oauth.Token{AccessToken: "secretaccesstokenhere"},
}
client := github.NewClient(t.Client())
gists, _, err := client.Gists.List("", nil)
if err != nil {
fmt.Println(err)
} else {
for _, g := range gists {
fmt.Printf("%v\n\n", g.Files)
}
}
}
And I get the following output:
map[TODO.md:github.GistFile{Size:166, Filename:"TODO.md", RawURL:"somerawurlhere"}]
map[fourcore.c:github.GistFile{Size:309, Filename:"fourcore.c", RawURL:"somerawurlhere"}]
map[coretest.cpp:github.GistFile{Size:160, Filename:"coretest.cpp", RawURL:"somerawurlhere"}]
What I would like to print is "ID / FILENAME". I understand that I need to extract the ID from Gist type and Filename from above map but I wasn't able to find a way to do that. How do I do that? Help would be greatly appreciated.
P.S: Here is the documentation describing Gist type.
答案1
得分: 1
你有一个名为Files的映射,其中文件名存储在类型为GistFilename的key变量中,而ID存储在类型为Gist的变量中。因此,你需要有两个范围循环-一个用于Gists,另一个用于Files。
类似于这样:
for _, g := range gists {
for filename, _ := range g.Files {
fmt.Printf("%v / %v\n", *g.ID, filename)
}
}
完整代码:
package main
import (
"code.google.com/p/goauth2/oauth"
"fmt"
"github.com/google/go-github/github"
)
func main() {
t := &oauth.Transport{
Token: &oauth.Token{AccessToken: "secretaccesstokenhere"},
}
client := github.NewClient(t.Client())
gists, _, err := client.Gists.List("", nil)
if err != nil {
fmt.Println(err)
return
}
for _, g := range gists {
for filename, _ := range g.Files {
fmt.Printf("%v / %v\n", *g.ID, filename)
}
}
}
英文:
You have Files map, where filename is stored in key variable of type GistFilename, and ID is in Gist type variable. So you have to have two range's - one for Gists, other for Files.
Something like this:
for _, g := range gists {
for filename, _ := range g.Files {
fmt.Printf("%v / %v\n", *g.ID, filename)
}
}
Full code:
package main
import (
"code.google.com/p/goauth2/oauth"
"fmt"
"github.com/google/go-github/github"
)
func main() {
t := &oauth.Transport{
Token: &oauth.Token{AccessToken: "secretaccesstokenhere"},
}
client := github.NewClient(t.Client())
gists, _, err := client.Gists.List("", nil)
if err != nil {
fmt.Println(err)
return
}
for _, g := range gists {
for filename, _ := range g.Files {
fmt.Printf("%v / %v\n", *g.ID, filename)
}
}
}
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库,让每个人都能够通过互相帮助和分享经验来进步。
评论