英文:
How can I initialize a type that is a pointer to a struct in Go?
问题
例如：
type Foo struct {
x int
}
var foo *Foo = &Foo{5}
type Bar *struct {
x int
}
var bar Bar = ??
我该如何初始化 bar？
我意识到有一个解决方法：
type Bar *Foo
var bar Bar = &Foo{5}
但我想避免这种方法。
英文:
For example:
type Foo struct {
x int
}
var foo *Foo = &Foo{5}
type Bar *struct {
x int
}
var bar Bar = ??
How can I initialize bar?
I realize there is a workaround:
type Bar *Foo
var bar Bar = &Foo{5}
But I would like to avoid that.
答案1
得分: 5
type Bar *struct这种形式几乎没有理由使用。这个类型是一个指向匿名结构体的指针，所以你必须用一个匿名结构体来初始化它（或者如你指出的，一个等效的可转换的结构体类型）。
var b Bar = &struct{x int}{}
// 或者
b := Bar(&Foo{})
这个声明本质上与
type Bar *Foo
是相同的，这可能会更清楚你想要做什么。
但是再次强调，这不是惯用的写法，在团队环境或公共接口中使用这种写法可能会遇到阻力（例如，我个人不会通过这种写法进行代码审查）。
英文:
There's [probably] no reason to ever use the form type Bar *struct. The type is a pointer to an anonymous struct, so you have to initialize it with an anonymous struct (or as you point out, an equivalent, convertible struct type).
var b Bar = &struct{x int}{}
// or
b := Bar(&Foo{})
The declaration is essentially the same is
type Bar *Foo
Which may make it a little more clear what you're trying to do.
But again, this is non-idiomatic, and you will probably encounter resistance using this in a team setting or public interface (i.e. I personally wouldn't pass this is code review)
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论