英文:
What is the fastest way to append one array to another in Go?
问题
假设我在Go语言中有数组A和B。将B的所有值追加到A的最快方法是什么？
英文:
Suppose that I have arrays A and B in Go. What is the fastest way to append all the values of B to A?
答案1
得分: 18
在Go语言中，数组（Arrays）是次要的，切片（Slices）才是更常用的方式。Go语言提供了内置的append()函数来追加切片：
a := []int{1, 2, 3}
b := []int{4, 5}
a = append(a, b...)
fmt.Println(a)
输出结果为：
[1 2 3 4 5]
你可以在Go Playground上尝试运行代码。
注意：
在Go语言中，数组的大小是固定的：一旦创建了数组，就无法增加其大小，因此无法向其追加元素。如果需要追加元素，你需要分配一个新的更大的数组，足够容纳两个数组中的所有元素。而切片则更加灵活。
在Go语言中，数组非常“不灵活”，甚至数组的大小也是其类型的一部分。例如，数组类型[2]int与[3]int是不同的类型，因此即使你创建了一个用于添加/追加[2]int类型数组的辅助函数，你也无法将其用于追加[3]int类型的数组！
阅读以下文章以了解更多关于数组和切片的知识：
英文:
Arrays in Go are secondary, slices are the way to go. Go provides a built-in append() function to append slices:
a := []int{1, 2, 3}
b := []int{4, 5}
a = append(a, b...)
fmt.Println(a)
Output:
[1 2 3 4 5]
Try it on the Go Playground.
Notes:
Arrays in Go are fixed sizes: once an array is created, you cannot increase its size so you can't append elements to it. If you would have to, you would need to allocate a new, bigger array; big enough to hold all the elements from the 2 arrays. Slices are much more flexible.
Arrays in Go are so "inflexible" that even the size of the array is part of its type so for example the array type [2]int is distinct from the type [3]int so even if you would create a helper function to add/append arrays of type [2]int you couldn't use that to append arrays of type [3]int!
Read these articles to learn more about arrays and slices:
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