英文:
How to access elements from slice using index which is passed by reference in golang
问题
我将为您翻译以下内容：
我将一个切片的引用传递给一个函数，并在函数内部对切片进行更改。同时，我尝试使用索引从切片中访问一个元素。在golang中，它会抛出异常。通过引用传递的方式，访问切片中的元素的最佳方法是什么？
您可以在这里找到一个示例代码。[参考：http://www.reddit.com/r/golang/comments/283vpk/help_with_slices_and_passbyreference/ ]。由于我的代码很庞大，我添加了一个示例。
package main
import "fmt"
type mystruct struct {
val int
}
func main() {
var s1 []mystruct
var s2 []mystruct
onlyPassing(&s1)
s2 = returningToo(s2)
fmt.Printf("%#v\n%#v", s1, s2)
}
func onlyPassing(s *[]mystruct) {
*s = append(*s, mystruct{1})
m := (*s)[0]
}
func returningToo(s []mystruct) []mystruct {
s = append(s, mystruct{1})
return s
}
您可以在这里找到实现代码1。有人可以帮助我吗？
英文:
I passed a reference of a slice to a function and I am making changes in the slice inside the function. Also I am trying to access an element from the slice using index. It is throwing exception in golang. What is the best way to access an element from a slice by index which is passed by reference?
You can find a sample code here. [ref : http://www.reddit.com/r/golang/comments/283vpk/help_with_slices_and_passbyreference/ ]. Since my code is huge I added a sample.
package main
import "fmt"
type mystruct struct {
val int
}
func main() {
var s1 []mystruct
var s2 []mystruct
onlyPassing(&s1)
s2 = returningToo(s2)
fmt.Printf("%#v\n%#v", s1, s2)
}
func onlyPassing(s *[]mystruct) {
*s = append(*s, mystruct{1})
m := *s[0]
}
func returningToo(s []mystruct) []mystruct {
s = append(s, mystruct{1})
return s
}
And you can find the implementation here. Could anyone help me on this.
答案1
得分: 25
索引运算符不会自动解引用指针。你需要使用括号来指定解引用的内容。
m := (*s)[0]
英文:
The index operator doesn't automatically dereference pointers. You need to use parentheses to specify what is dereferenced.
m := (*s)[0]
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