英文:
Go: Varint returns different values than read
问题
为什么binary.Varint返回的结果与binary.Read不同？
package main
import "fmt"
import "encoding/binary"
import "bytes"
func main() {
b := []byte{0x18, 0x2d, 0x44, 0x54, 0xfb, 0x21, 0x09, 0x40}
var i1 int64
buf := bytes.NewBuffer(b)
binary.Read(buf, binary.LittleEndian, &i1)
fmt.Printf("%s, %d\n", i1, i1)
i2, _ := binary.Varint(b)
fmt.Printf("%s, %d\n", i2, i2)
}
返回结果：
%!s(int64=4614256656552045848), 4614256656552045848
%!s(int64=12), 12
这是一个指向playground的链接：https://play.golang.org/p/vlrl_CHq0v
英文:
Why does binary.Varint return different results than binary.Read?
package main
import "fmt"
import "encoding/binary"
import "bytes"
func main() {
b := []byte{0x18, 0x2d, 0x44, 0x54, 0xfb, 0x21, 0x09, 0x40}
var i1 int64
buf := bytes.NewBuffer(b)
binary.Read(buf, binary.LittleEndian, &i1)
fmt.Printf("%s, %d\n", i1, i1)
i2, _ := binary.Varint(b)
fmt.Printf("%s, %d\n", i2, i2)
}
Returns:
> %!s(int64=4614256656552045848), 4614256656552045848
> %!s(int64=12), 12
Here's a link to the playground: https://play.golang.org/p/vlrl_CHq0v
答案1
得分: 3
Varint（变长整数）是一种特定的编码方式，这意味着它从网络或文件中读取的字节值并不是实际的整数值，而是一种编码方式。而另一方面，Read（读取）只是按照你传递给它的字节顺序读取字节。
英文:
Varint is a specific encoding, that means that the byte value it reads off the wire/from the file is not an actually integer value, but an encoding. Read on the other hand, just reads bytes in whichever byte order you passed to it.
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