英文:
Gorilla Mux for sub path Routing
问题
我有以下路由：
router.Methods("POST").Path("/my_post_01").HandlerFunc(myHandler1)router.Methods("GET").Path("/my_get_01").HandlerFunc(myHandler2)router.Methods("POST").Path("/my_post_02").HandlerFunc(myHandler3)router.Methods("GET").Path("/my_get_02").HandlerFunc(myHandler4)router.Methods("POST").Path("/my_post_03").HandlerFunc(myHandler5)router.Methods("GET").Path("/my_get_03").HandlerFunc(myHandler6)router.Methods("POST").Path("/my_post_04").HandlerFunc(myHandler7)router.Methods("GET").Path("/my_get_04").HandlerFunc(myHandler8)router.Methods("POST").Path("/my_post_05").HandlerFunc(myHandler9)router.Methods("GET").Path("/my_get_05").HandlerFunc(myHandler10)
随着路由越来越多，管理起来变得越来越困难。
我想要做这样的事情：
router.Path("/my/*").HandleFunc(mypackage.RegisterHandler)
所有的处理程序都分离在另一个包中。
有没有办法在另一个包中匹配这些路径？
谢谢，
英文:
I have the following routes:
router.Methods("POST").Path("/my_post_01").HandlerFunc(myHandler1)router.Methods("GET").Path("/my_get_01").HandlerFunc(myHandler2)router.Methods("POST").Path("/my_post_02").HandlerFunc(myHandler3)router.Methods("GET").Path("/my_get_02").HandlerFunc(myHandler4)router.Methods("POST").Path("/my_post_03").HandlerFunc(myHandler5)router.Methods("GET").Path("/my_get_03").HandlerFunc(myHandler6)router.Methods("POST").Path("/my_post_04").HandlerFunc(myHandler7)router.Methods("GET").Path("/my_get_04").HandlerFunc(myHandler8)router.Methods("POST").Path("/my_post_05").HandlerFunc(myHandler9)router.Methods("GET").Path("/my_get_05").HandlerFunc(myHandler10)
As I have more and more routes, it gets harder to manage.
I want to do something like:
router.Path("/my/*").HandleFunc(mypackage.RegisterHandler)
with all handlers being separated in another package
Is there any way that I can match those paths in a separate package?
Thanks,
答案1
得分: 2
你可以为你的路由器创建一个包，然后导入该包并添加你的路由。
路由器
package routervar Router = mux.NewRouter()// 处理 "/my/" 路由var MyRouter = Router.PathPrefix("/my").Subrouter()
另一个包
import "/path/to/router"func init() {router.MyRouter.Methods("POST").Path("/post_01").HandlerFunc(myHandler1)}
在主函数中
import "/path/to/router"func main() {http.Handle("/", router.Router)//...}
英文:
You could create a package for your router then import said package and add your routes.
Router
package routervar Router = mux.NewRouter()// handle "/my/" routesvar MyRouter = Router.PathPrefix("/my").Subrouter()
another package
import "/path/to/router"func init() {router.MyRouter.Methods("POST").Path("/post_01").HandlerFunc(myHandler1)}
In main
import "/path/to/router"func main() {http.Handle("/", router.Router)//...}
答案2
得分: 2
如果你能从请求URL中提取id并在通用处理程序中处理它，那将会更好。
实际上，你离目标并不远，只需修改你的路由器如下：
r := mux.NewRouter()r.Methods("POST").HandleFunc("/articles/{article_id:[0-9]+}", ArticlePostHandler)
article_id是参数名，[0-9]+是用于匹配它的正则表达式。
在ArticlePostHandler中（你可以从另一个包中导入它），使用mux.Vars来获取id，像这样：
func ArticlePostHandler(resp http.ResponseWriter, req *http.Request) {articleId := mux.Vars(req)["article_id"]// 根据需要处理`articleId`}
文档：http://www.gorillatoolkit.org/pkg/mux
英文:
It would be a lot better if you could extract id from the request URL and handle it in a generic handler.
Actually, it is not far from where you are right now, modify you router like this:
r := mux.NewRouter()r.Methods("POST").HandleFunc("/articles/{article_id:[0-9]+}", ArticlePostHandler)
article_id is the parameter name and [0-9]+ is the regexp to match it.
And in the ArticlePostHandler (you could import it from another package), use mux.Vars to get the id, like this:
func ArticlePostHandler(resp http.ResponseWriter, req *http.Request) {articleId := mux.Vars(req)["article_id"]// do whatever you want with `articleId`}
Document: http://www.gorillatoolkit.org/pkg/mux
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