英文:
Gorilla Mux for sub path Routing
问题
我有以下路由:
router.Methods("POST").Path("/my_post_01").HandlerFunc(myHandler1)
router.Methods("GET").Path("/my_get_01").HandlerFunc(myHandler2)
router.Methods("POST").Path("/my_post_02").HandlerFunc(myHandler3)
router.Methods("GET").Path("/my_get_02").HandlerFunc(myHandler4)
router.Methods("POST").Path("/my_post_03").HandlerFunc(myHandler5)
router.Methods("GET").Path("/my_get_03").HandlerFunc(myHandler6)
router.Methods("POST").Path("/my_post_04").HandlerFunc(myHandler7)
router.Methods("GET").Path("/my_get_04").HandlerFunc(myHandler8)
router.Methods("POST").Path("/my_post_05").HandlerFunc(myHandler9)
router.Methods("GET").Path("/my_get_05").HandlerFunc(myHandler10)
随着路由越来越多,管理起来变得越来越困难。
我想要做这样的事情:
router.Path("/my/*").HandleFunc(mypackage.RegisterHandler)
所有的处理程序都分离在另一个包中。
有没有办法在另一个包中匹配这些路径?
谢谢,
英文:
I have the following routes:
router.Methods("POST").Path("/my_post_01").HandlerFunc(myHandler1)
router.Methods("GET").Path("/my_get_01").HandlerFunc(myHandler2)
router.Methods("POST").Path("/my_post_02").HandlerFunc(myHandler3)
router.Methods("GET").Path("/my_get_02").HandlerFunc(myHandler4)
router.Methods("POST").Path("/my_post_03").HandlerFunc(myHandler5)
router.Methods("GET").Path("/my_get_03").HandlerFunc(myHandler6)
router.Methods("POST").Path("/my_post_04").HandlerFunc(myHandler7)
router.Methods("GET").Path("/my_get_04").HandlerFunc(myHandler8)
router.Methods("POST").Path("/my_post_05").HandlerFunc(myHandler9)
router.Methods("GET").Path("/my_get_05").HandlerFunc(myHandler10)
As I have more and more routes, it gets harder to manage.
I want to do something like:
router.Path("/my/*").HandleFunc(mypackage.RegisterHandler)
with all handlers being separated in another package
Is there any way that I can match those paths in a separate package?
Thanks,
答案1
得分: 2
你可以为你的路由器创建一个包,然后导入该包并添加你的路由。
路由器
package router
var Router = mux.NewRouter()
// 处理 "/my/" 路由
var MyRouter = Router.PathPrefix("/my").Subrouter()
另一个包
import "/path/to/router"
func init() {
router.MyRouter.Methods("POST").Path("/post_01").HandlerFunc(myHandler1)
}
在主函数中
import "/path/to/router"
func main() {
http.Handle("/", router.Router)
//...
}
英文:
You could create a package for your router then import said package and add your routes.
Router
package router
var Router = mux.NewRouter()
// handle "/my/" routes
var MyRouter = Router.PathPrefix("/my").Subrouter()
another package
import "/path/to/router"
func init() {
router.MyRouter.Methods("POST").Path("/post_01").HandlerFunc(myHandler1)
}
In main
import "/path/to/router"
func main() {
http.Handle("/", router.Router)
//...
}
答案2
得分: 2
如果你能从请求URL中提取id
并在通用处理程序中处理它,那将会更好。
实际上,你离目标并不远,只需修改你的路由器如下:
r := mux.NewRouter()
r.Methods("POST").HandleFunc("/articles/{article_id:[0-9]+}", ArticlePostHandler)
article_id
是参数名,[0-9]+
是用于匹配它的正则表达式。
在ArticlePostHandler
中(你可以从另一个包中导入它),使用mux.Vars
来获取id,像这样:
func ArticlePostHandler(resp http.ResponseWriter, req *http.Request) {
articleId := mux.Vars(req)["article_id"]
// 根据需要处理`articleId`
}
文档:http://www.gorillatoolkit.org/pkg/mux
英文:
It would be a lot better if you could extract id
from the request URL and handle it in a generic handler.
Actually, it is not far from where you are right now, modify you router like this:
r := mux.NewRouter()
r.Methods("POST").HandleFunc("/articles/{article_id:[0-9]+}", ArticlePostHandler)
article_id
is the parameter name and [0-9]+
is the regexp to match it.
And in the ArticlePostHandler
(you could import it from another package), use mux.Vars
to get the id, like this:
func ArticlePostHandler(resp http.ResponseWriter, req *http.Request) {
articleId := mux.Vars(req)["article_id"]
// do whatever you want with `articleId`
}
Document: http://www.gorillatoolkit.org/pkg/mux
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