英文:
How to replace occured strings with a counter in Go regexp?
问题
例如，在这个句子中，
让自由从纽约的崇山峻岭中回响。让自由从宾夕法尼亚州的高耸阿勒格尼山脉中回响。让自由从科罗拉多州的雪-capped洛基山脉中回响。让自由从加利福尼亚州的曲线斜坡中回响。
如何用"[1] 让自由"，"[2] 让自由2"等替换"让自由"。
我搜索了Go的regexp包，未能找到与增加计数器相关的内容。（只找到了ReplaceAllStringFunc，但我不知道如何使用它。）
英文:
For example, in this sentence,
Let freedom ring from the mighty mountains of New York. Let freedom ring from the heightening Alleghenies of Pennsylvania. Let freedom ring from the snow-capped Rockies of Colorado. Let freedom ring from the curvaceous slopes of California.
how to replace "Let freedom" with
"[1] Let freedom",
"[2] Let freedom2", and so on.
I searched the Go regexp package, failed to find anything related increase counter. (Only find the ReplaceAllStringFunc, but I don't know how to use it.)
答案1
得分: 2
你需要像这样的代码：
import (
"fmt"
"regexp"
)
func main() {
input := "Let freedom"
r, i := regexp.MustCompile("Let freedom"), 0
result := r.ReplaceAllStringFunc(input, func(m string) string {
i += 1
if i == 1 {
return "[1]" + m
}
return fmt.Sprintf("[%d] %s%d", i, m, i)
})
fmt.Println(result)
}
确保已导入所需的包。上述代码通过使用Let freedom作为正则表达式，并使用一些条件来返回预期的结果。
英文:
You need something like this
r, i := regexp.MustCompile("Let freedom"), 0
r.ReplaceAllStringFunc(input, func(m string) string {
i += 1
if i == 1 {
return "[1]" + m
}
return fmt.Sprintf("[%d] %s%d", i, m, i)
})
Make sure you've imported required packages.. The above works by using Let freedom as the regex and then using some conditions to return what is intended.
答案2
得分: 0
你需要在连续调用函数之间以某种方式共享计数器。一种方法是构建闭包。你可以这样做：
package main
import (
"fmt"
"regexp"
)
func main() {
str := "Let freedom ring from the mighty mountains of New York. Let freedom ring from the heightening Alleghenies of Pennsylvania. Let freedom ring from the snow-capped Rockies of Colorado. Let freedom ring from the curvaceous slopes of California."
counter := 1
repl := func(match string) string {
old := counter
counter++
if old != 1 {
return fmt.Sprintf("[%d] %s%d", old, match, old)
}
return fmt.Sprintf("[%d] %s", old, match)
}
re := regexp.MustCompile("Let freedom")
str2 := re.ReplaceAllStringFunc(str, repl)
fmt.Println(str2)
}
这段代码使用闭包来共享计数器。在每次调用repl函数时，计数器会递增，并将计数器的值与匹配的字符串一起返回。最终，str2将包含替换后的字符串。
英文:
You need to somehow share counter between successive calls to your function. One way to do this is to construct closure. You can do it this way:
package main
import (
"fmt"
"regexp"
)
func main() {
str := "Let freedom ring from the mighty mountains of New York. Let freedom ring from the heightening Alleghenies of Pennsylvania. Let freedom ring from the snow-capped Rockies of Colorado. Let freedom ring from the curvaceous slopes of California."
counter := 1
repl := func(match string) string {
old := counter
counter++
if old != 1 {
return fmt.Sprintf("[%d] %s%d", old, match, old)
}
return fmt.Sprintf("[%d] %s", old, match)
}
re := regexp.MustCompile("Let freedom")
str2 := re.ReplaceAllStringFunc(str, repl)
fmt.Println(str2)
}
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