英文:
How to concatenate strings and ints natively?
问题
我目前找到的在Go语言中将字符串与整数连接的最短（最简洁）方法如下：
"blahblah" + strconv.Itoa(42) + "something"
（导入strconv包）
由于Go语言的一个原则是保持简单，我对于需要导入一个包来完成这个操作感到惊讶。
因此，我的问题是：是否有任何本地（更简洁）的方法来实现这个操作？
显然，我尝试了以下语法，但它甚至无法编译通过：
"blahblah" + 42 + "something"
我还尝试了下面这个语法，实际上它是对值进行了类型转换，这不是我想要的（它将值转换为相应的Unicode字符，对于值42，它将是*）：
"blahblah" + string(42) + "something"
英文:
The shortest (cleanest) way I have found so far to concatenate strings with ints in Go is the following:
"blahblah" + strconv.Itoa(42) + "something"
(importing package strconv)
Since one motto of the Go language is to be simple, I was surprised to have to import a package to do this.
Hence, my question: is there any native (thus cleaner) way of doing this?
Obviously, I tried the following syntax, which does not even compile:
"blahblah" + 42 + "something"
I also tried that one, which is in fact a cast of the value, which is not what I want (it converts the value to the corresponding unicode character, which would be * for the value 42):
"blahblah" + string(42) + "something"
答案1
得分: 1
这将起到作用（尽管它使用了反射）：
str := fmt.Sprintf("blah %d blah", 42)
英文:
This'll do the trick (it uses reflection though):
str := fmt.Sprintf("blah %d blah", 42)
答案2
得分: -1
你可以使用不同的打印命令来实现你想要的效果。虽然不是一行代码，但它可以工作。
package main
import "fmt"
func main() {
fmt.Print("blahblah")
fmt.Print(42)
fmt.Print("something")
}
英文:
You can use different print commands to do what you want. It's not a one liner, but it works.
package main
import "fmt"
func main() {
fmt.Print("blahblah")
fmt.Print(42)
fmt.Print("something")
}
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