如何将具有动态字段的JSON对象映射到Go结构体中

huangapple go评论91阅读模式
英文:

How to map JSON objects with dynamic fields to Go structs

问题

我正在使用Go开发一个网站,并将其连接到Elastic Search。在Elastic Search中,我可以为索引类型设置动态字段。当我从Elastic Search中读取文档时,它将返回一个JSON对象作为结果,其中可能包含具有动态名称(或用户定义字段)的字段。

我可以获取JSON结果并将其解组为Go结构体,但我不知道将这些动态字段保留为Go结构体的最佳方法是什么。

这是我正在做的。例如,如果我从Elastic Search获取一个联系人文档,它可能如下所示:

{  
   "EmailAddress": "test@test.com",
   "Name": "Test Contact",
   "Phone": "17894785236",
   "City": "San Francisco",
   "State": "California"
}

而Contact的Go结构体如下所示:

type Contact struct {
	EmailAddress            string
	Name                    string
	Phone                   string
    CustomFields            map[string]interface{}
}

我实现了MarshalerUnmarshaler来重写对象的编组和解组方式。

func (c *Contact) MarshalJSON() ([]byte, error) {
	contactMap := make(map[string]interface{})
	contactMap["EmailAddress"] = c.EmailAddress
	contactMap["Name"] = c.Name
	contactMap["Phone"] = c.Phone

	for k, v := range c.CustomFields {
		contactMap[k] = v
	}

	return json.Marshal(contactMap)
}

func (c *Contact) UnmarshalJSON(data []byte) error {
	var contactMap map[string]interface{}

	if c == nil {
		return errors.New("RawString: UnmarshalJSON on nil pointer")
	}

	if err := json.Unmarshal(data, &contactMap); err != nil {
		return err
	}

	c.EmailAddress = contactMap["EmailAddress"].(string)
	c.Name = contactMap["Name"].(string)
	c.Phone = contactMap["Phone"].(string)

	for key, val := range contactMap {
		if key != "EmailAddress" && key != "Name" && key != "Phone" {
			c.CustomFields[key] = value
		}
	}

	return nil
}

这是最佳的方法吗?你有什么建议?

英文:

I am developing a website using Go and connecting it to Elastic Search. In Elastic Search I can have dynamic fields for index types. When I read a document from Elastic Search it will return a JSON object as the result, which can include fields with dynamic names (or user defined fields).

I can get the JSON result and unmarshal it into a Go struct, but I do not know what is the best way to keep those dynamic fields as part of the Go struct.

This is what I am doing. For example, if I get a document for a Contact from Elastic Search it may look something like this:

{  
   "EmailAddress": "test@test.com",
   "Name": "Test Contact",
   "Phone": "17894785236",
   "City": "San Francisco",
   "State": "California"
}

And the Go struct for Contact is:

type Contact struct {
	EmailAddress            string
	Name                    string
	Phone                   string
    CustomFields            map[string]interface{}
}

And I implement Marshaler and Unmarshaler to override how the object is Marshaled and Unmarshalled.

func (c *Contact) MarshalJSON() ([]byte, error) {
	contactMap := make(map[string]interface{})
	contactMap["EmailAddress"] = c.EmailAddress
	contactMap["Name"] = c.Name
	contactMap["Phone"] = c.Phone

	for k, v := range c.CustomFields {
		contactMap[k] = v
	}

	return json.Marshal(contactMap)
}

func (c *Contact) UnmarshalJSON(data []byte) error {
	var contactMap map[string]interface{}

	if c == nil {
		return errors.New("RawString: UnmarshalJSON on nil pointer")
	}

	if err := json.Unmarshal(data, &contactMap); err != nil {
		return err
	}

	c.EmailAddress = contactMap["EmailAddress"].(string)
	c.Name = contactMap["Name"].(string)
	c.Phone = contactMap["Phone"].(string)

	for key, val := range contactMap {
		if key != "EmailAddress" && key != "Name" && Key != "Phone" {
			c.CustomFields[key] = value
		}
	}

	return nil
}

Is this the best way to do this? What would you recommend?

答案1

得分: 5

只需进行一些小的清理

var contactMap map[string]interface{}

if c == nil {
    return errors.New("RawString: UnmarshalJSON on nil pointer")
}

if err := json.Unmarshal(data, &contactMap); err != nil {
    return err
}

for key, val := range contactMap {
    switch key {
        case "EmailAddress":
            c.EmailAddress = val.(string)
        case "Name":
            c.Name = val.(string)
        case "Phone":
            c.Phone = val.(string)
        default:
            c.CustomFields[key] = val
    }
}
}
英文:

Just add little cleanup

var contactMap map[string]interface{}

if c == nil {
	return errors.New("RawString: UnmarshalJSON on nil pointer")
}

if err := json.Unmarshal(data, &contactMap); err != nil {
	return err
}

for key, val := range contactMap {
	switch key {
		case "EmailAddress":
			c.EmailAddress = val.(string)
		case "Name":
			c.Name = val.(string)
		case "Phone":
			c.Phone = val.(string)
		default:
			c.CustomFields[key] = val
		}
	}
}

答案2

得分: 4

正如Simon在评论中指出的那样,如果JSON的结构是固定的,使用一个大的**map[string]interface{}**并不理想。最好的方法是使用结构体并使用http://golang.org/pkg/encoding/json/#Unmarshal进行解组(参考示例:http://play.golang.org/p/cDTe8x4xLk)。

但是对于结构未知的大型JSON数据块,您的实现完全有效。

编辑:添加了示例链接

英文:

As Simon has pointed out in comment, using one big map[string]interface{} isn't ideal if the structure of the json is fixed. Best way then is to use structure and unmarshall it using http://golang.org/pkg/encoding/json/#Unmarshal. (refer the example: http://play.golang.org/p/cDTe8x4xLk)

But for large json blob, for which structure is not known beforehand, your implementation works perfectly.

edit: added link to example

huangapple
  • 本文由 发表于 2014年12月16日 04:49:49
  • 转载请务必保留本文链接:https://go.coder-hub.com/27492888.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定