英文:
More easy way of using Interfaces to map YAML dynamically?
问题
我正在尝试动态解析一个YAML文件(因此没有结构体)。
package main
import (
"fmt"
"gopkg.in/yaml.v2"
"log"
)
func main() {
var out = `
a: First!
f: Second
b:
c:
f: Third
`
m := make(map[interface{}]interface{})
err := yaml.Unmarshal([]byte(out), &m)
if err != nil {
log.Fatal(err)
}
fmt.Println(m["b"].(map[interface{}]interface{})["c"].(map[interface{}]interface{})["f"])
}
每次我需要访问一个子键时,我被迫将相关的map变量转换为(map[interface{}]interface{})。这对我来说有点麻烦,因为我必须遍历整个map。
在Go中,有没有更简单的方法来解析YAML文件?
英文:
I am trying to parse a yaml file dynamically (Therefore no struct).
package main
import (
"fmt"
"gopkg.in/yaml.v2"
"log"
)
func main() {
var out = `
a: First!
f: Second
b:
c:
f: Third
`
m := make(map[interface{}]interface{})
err := yaml.Unmarshal([]byte(out), &m)
if err != nil {
log.Fatal(err)
}
fmt.Println(m["b"].(map[interface{}]interface{})["c"].(map[interface{}]interface{})["f"])
}
Everytime I have to access a subkey, I am forced to convert map variable in question to (map[interface{}]interface{}). This is causing bit of a hassle for me as I have to iterate through the map.
Is there any easier method for parsing YAML file in Go?
答案1
得分: 1
另一种方法是将yaml数据结构展平为键值对映射,其中键和值都是字符串。然后,如果你需要实际的类型(例如5是一个整数),你可以自己进行转换。示例代码如下:
func main() {
any := map[string]interface{}{}
err := yaml.Unmarshal([]byte(out), &any)
if err != nil {
log.Fatal(err)
}
flatmap := map[string]string{}
for k, v := range any {
flatten(k, v, flatmap)
}
for k, v := range flatmap {
fmt.Println(k, "=", v)
}
}
func flatten(prefix string, value interface{}, flatmap map[string]string) {
submap, ok := value.(map[interface{}]interface{})
if ok {
for k, v := range submap {
flatten(prefix+"."+k.(string), v, flatmap)
}
return
}
stringlist, ok := value.([]interface{})
if ok {
flatten(fmt.Sprintf("%s.size", prefix), len(stringlist), flatmap)
for i, v := range stringlist {
flatten(fmt.Sprintf("%s.%d", prefix, i), v, flatmap)
}
return
}
flatmap[prefix] = fmt.Sprintf("%v", value)
}
这段代码将yaml数据结构展平为键值对的形式,并打印出展平后的结果。你可以根据需要进行修改和使用。
英文:
Another approach is to flatten the yaml data structure into a key,value map in which keys and values are strings. Then if you need the actual type (5 being an int) you can do the conversion yourself. Example:
"a" = "First!"
"f" = "Second"
"b.c.f" = "Third"
"b.c.g.size" = "2"
"b.c.g.0 = "zero"
"b.c.g.1 = "one"
In Go:
func main() {
any := map[string]interface{}{}
err := yaml.Unmarshal([]byte(out), &any)
if err != nil {
log.Fatal(err)
}
flatmap := map[string]string{}
for k, v := range any {
flatten(k, v, flatmap)
}
for k, v := range flatmap {
fmt.Println(k, "=", v)
}
}
func flatten(prefix string, value interface{}, flatmap map[string]string) {
submap, ok := value.(map[interface{}]interface{})
if ok {
for k, v := range submap {
flatten(prefix+"."+k.(string), v, flatmap)
}
return
}
stringlist, ok := value.([]interface{})
if ok {
flatten(fmt.Sprintf("%s.size", prefix), len(stringlist), flatmap)
for i, v := range stringlist {
flatten(fmt.Sprintf("%s.%d", prefix, i), v, flatmap)
}
return
}
flatmap[prefix] = fmt.Sprintf("%v", value)
}
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库,让每个人都能够通过互相帮助和分享经验来进步。
评论