如何漂亮地打印变量

huangapple go评论88阅读模式
英文:

How to pretty print variables

问题

在Go语言中是否有类似Ruby的awesome_print的功能?

例如,在Ruby中,你可以这样写:

require 'ap'
x = {a:1,b:2} // 也适用于类
ap x

输出结果将会是:

{ 
  "a" => 1,
  "b" => 2
}

在Go语言中,最接近的功能是使用Printf("%#v", x)

英文:

Is there something like Ruby's awesome_print in Go?

For example in Ruby you could write:

require 'ap'
x = {a:1,b:2} // also works for class
ap x

the output would be:

{ 
  "a" => 1,
  "b" => 2
}

closest thing that I could found is Printf("%#v", x)

答案1

得分: 122

如果你的目标是避免导入第三方包,另一个选择是使用 json.MarshalIndent

x := map[string]interface{}{"a": 1, "b": 2}
b, err := json.MarshalIndent(x, "", "  ")
if err != nil {
    fmt.Println("error:", err)
}
fmt.Print(string(b))

输出:

{
    "a": 1,
    "b": 2
}

工作示例:http://play.golang.org/p/SNdn7DsBjy

英文:

If your goal is to avoid importing a third-party package, your other option is to use json.MarshalIndent:

x := map[string]interface{}{"a": 1, "b": 2}
b, err := json.MarshalIndent(x, "", "  ")
if err != nil {
	fmt.Println("error:", err)
}
fmt.Print(string(b))

Output:

{
    "a": 1,
    "b": 2
}

Working sample: http://play.golang.org/p/SNdn7DsBjy

答案2

得分: 27

没问题,以下是翻译好的内容:

不用担心,我找到一个:https://github.com/davecgh/go-spew

// 导入 "github.com/davecgh/go-spew/spew" 包
x := map[string]interface{}{"a":1,"b":2}
spew.Dump(x)

输出结果如下:

(map[string]interface {}) (len=2) {
 (string) (len=1) "a": (int) 1,
 (string) (len=1) "b": (int) 2
}
英文:

Nevermind, I found one: https://github.com/davecgh/go-spew

// import "github.com/davecgh/go-spew/spew"
x := map[string]interface{}{"a":1,"b":2}
spew.Dump(x)

Would give an output:

(map[string]interface {}) (len=2) {
 (string) (len=1) "a": (int) 1,
 (string) (len=1) "b": (int) 2
}

答案3

得分: 14

如果你想要漂亮的彩色输出,你可以使用 pp

https://github.com/k0kubun/pp

import "github.com/k0kubun/pp"
...
pp.Print(m)

如何漂亮地打印变量

英文:

If you want pretty coloured output, you can use pp.

https://github.com/k0kubun/pp

import "github.com/k0kubun/pp"
...
pp.Print(m)

如何漂亮地打印变量

答案4

得分: 4

我刚刚根据Simon的答案编写了一个简单的函数:

func dump(data interface{}) {
    b, _ := json.MarshalIndent(data, "", "  ")
    fmt.Print(string(b))
}

这个函数的作用是将数据转换为JSON格式并打印出来。

英文:

I just wrote a simple function based on Simons answer:

func dump(data interface{}){
	b,_:=json.MarshalIndent(data, "", "  ")
	fmt.Print(string(b))
}

答案5

得分: 3

我来帮你翻译:

我想使用这样的代码片段:

func printMap(m map[string]string) {
    var maxLenKey int
    for k, _ := range m {
        if len(k) > maxLenKey {
            maxLenKey = len(k)
        }
    }

    for k, v := range m {
        fmt.Println(k + ": " + strings.Repeat(" ", maxLenKey - len(k)) + v)
    }
}

输出将会是这样的:

short_key:       value1
really_long_key: value2

告诉我,是否有更简单的方法来实现相同的对齐效果。

英文:

I came up to use snippet like this:

func printMap(m map[string]string) {
    var maxLenKey int
    for k, _ := range m {
	    if len(k) > maxLenKey {
		    maxLenKey = len(k)
	    }
    }

    for k, v := range m {
	    fmt.Println(k + ": " + strings.Repeat(" ", maxLenKey - len(k)) + v)
    }
}

The output will be like this:

short_key:       value1
really_long_key: value2

Tell me, if there's some simpler way to do the same alignment.

huangapple
  • 本文由 发表于 2014年11月25日 10:36:57
  • 转载请务必保留本文链接:https://go.coder-hub.com/27117896.html
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