英文:
Go regexp find word with apostrophe
问题
我正在尝试找到两个单词之间的子字符串，但是我的起始单词包含一个撇号，我似乎无法匹配它。
例如，在以下句子中：
bus driver drove steady although the bus's steering was going nuts.
我的搜索的正确答案应该是：
steering was going nuts
而不是：
driver ... nuts
我尝试了这个：
re := regexp.MustCompile("(?s)bus[\\'].*?nuts")
我还尝试了这个：
re := regexp.MustCompile("(?s)bus'.*?nuts")
似乎无法使其工作。
英文:
I am trying to find a substring between two words, but my starting word contains an apostrophe and I can't seem to match it.
For example, in this following sentence
bus driver drove steady although the bus's steering was going nuts.
the correct answer to my search should be:
steering was going nuts
and not:
driver ... nuts
I tried this
re := regexp.MustCompile("(?s)bus[\\\'].*?nuts")
I also tried this:
re := regexp.MustCompile("(?s)bus'.*?nuts")
Can't seem to make it work.
答案1
得分: 2
正确答案应该是"steering was going nuts"...
如果你想要这个子字符串作为匹配结果，你应该相应地调整你的正则表达式。
re := regexp.MustCompile(`(?s)bus's (.*?nuts)`)rm := re.FindStringSubmatch(str)if len(rm) != 0 {fmt.Printf("%q\n", rm[0]) // "bus's steering was going nuts"fmt.Printf("%q", rm[1]) // "steering was going nuts"}
英文:
>The correct answer to my search should be "steering was going nuts" ...
If you want that substring as your match result, you should adjust your regex accordingly.
re := regexp.MustCompile("(?s)bus's (.*?nuts)")rm := re.FindStringSubmatch(str)if len(rm) != 0 {fmt.Printf("%q\n", rm[0]) // "bus's steering was going nuts"fmt.Printf("%q", rm[1]) // "steering was going nuts"}
<kbd>GoPlay</kbd>
答案2
得分: 0
您可以使用字符串字面量（使用反引号）来包含单引号，并使用捕获组：
re := regexp.MustCompile(`(?s)bus'.\s+(.*?nuts)`)
参考这个示例：
var source_txt = `bus driver drove steady although the bus's steering was going nuts.`func main() {fmt.Printf("Experiment with regular expressions.\n")fmt.Printf("source text:\n")fmt.Println("--------------------------------")fmt.Printf("%s\n", source_txt)fmt.Println("--------------------------------")// a regular expressionregex := regexp.MustCompile(`(?s)bus'.\s+(.*?nuts)`)fmt.Printf("regex: '%v'\n", regex)matches := regex.FindStringSubmatch(source_txt)for i, v := range matches {fmt.Printf("match %2d: '%s'\n", i+1, v)}}
输出：
Experiment with regular expressions.source text:--------------------------------bus driver drove steady although the bus's steering was going nuts.--------------------------------regex: '(?s)bus'.\s+(.*?nuts)'match 1: 'bus's steering was going nuts'match 2: 'steering was going nuts'
FindStringSubmatch()函数用于：
在字符串
s中找到正则表达式的最左匹配以及其子表达式的匹配（如果有的话）
match[1]将是第一个捕获组。
英文:
You could use a string literal (with back quote) in order to include a single quote, with a capturing group:
re := regexp.MustCompile(`(?s)bus'.\s+(.*?nuts)`)
See this example:
var source_txt = `bus driver drove steady although the bus's steering was going nuts.`func main() {fmt.Printf("Experiment with regular expressions.\n")fmt.Printf("source text:\n")fmt.Println("--------------------------------")fmt.Printf("%s\n", source_txt)fmt.Println("--------------------------------")// a regular expressionregex := regexp.MustCompile(`(?s)bus'.\s+(.*?nuts)`)fmt.Printf("regex: '%v'\n", regex)matches := regex.FindStringSubmatch(source_txt)for i, v := range matches {fmt.Printf("match %2d: '%s'\n", i+1, v)}}
Output:
Experiment with regular expressions.source text:--------------------------------bus driver drove steady although the bus's steering was going nuts.--------------------------------regex: '(?s)bus'.\s+(.*?nuts)'match 1: 'bus's steering was going nuts'match 2: 'steering was going nuts'
The FindStringSubmatch() :
> identifying the leftmost match of the regular expression in s and the matches, if any, of its subexpressions
The match[1] would be the first capturing group.
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