英文:
Go: split byte.Buffer by newline
问题
你好！以下是你要翻译的内容：
对Go语言还比较新，遇到了一个问题：
var metrics bytes.Buffermetrics.WriteString("foo")metrics.WriteString("\n")metrics.WriteString("bar")metrics.WriteString("\n")
现在我想遍历这个metrics并按换行符进行分割。我尝试了以下代码：
for _, m := range strings.Split(metrics.String(), "\n") {log.Printf("metric: %s", m)}
但是我得到了以下错误信息：
./relay.go:71: m := strings.Split(metrics.String(), "\n") used as value
希望对你有帮助！如果你有任何其他问题，请随时提问。
英文:
Pretty new to Go and running into a problem like:
var metrics bytes.Buffermetrics.WriteString("foo")metrics.WriteString("\n")metrics.WriteString("bar")metrics.WriteString("\n")
Now I want to cycle through that metrics and split by newline. I tried
for m := strings.Split(metrics.String(), "\n") {log.Printf("metric: %s", m)}
but I get the following
./relay.go:71: m := strings.Split(metrics.String(), "\n") used as value
答案1
得分: 14
你可以使用bufio.Scanner来实现这个功能。具体的使用方法可以参考http://golang.org/pkg/bufio/#Scanner。
代码示例如下：
import ("bufio""bytes""log")func main() {var metrics bytes.Buffermetrics.WriteString("foo")metrics.WriteString("\n")metrics.WriteString("bar")metrics.WriteString("\n")scanner := bufio.NewScanner(&metrics)for scanner.Scan() {log.Printf("metric: %s", scanner.Text())}if err := scanner.Err(); err != nil {log.Fatal(err)}}
你可以在这里找到一个完整的示例：http://play.golang.org/p/xrFEGF3h5P
英文:
You can do this with a bufio.Scanner
Godoc at http://golang.org/pkg/bufio/#Scanner
Something like this:
var metrics bytes.Buffermetrics.WriteString("foo")metrics.WriteString("\n")metrics.WriteString("bar")metrics.WriteString("\n")scanner := bufio.NewScanner(&metrics)for scanner.Scan() {log.Printf("metric: %s", scanner.Text())}if err := scanner.Err(); err != nil {log.Fatal(err)}
A full example here: http://play.golang.org/p/xrFEGF3h5P
答案2
得分: 8
考虑到strings.Split()返回一个数组，使用range会更容易一些：
m := strings.Split(metrics.String(), "\n")for _, m := range strings.Split(metrics.String(), "\n") {log.Printf("metric: %s", m)}
注意，要从字符串中读取行，可以考虑使用bufio.ReadLine()或更好的bufio.Scanner：
const input = "Now is the winter of our discontent,\nMade glorious summer by this sun of York.\n"scanner := bufio.NewScanner(strings.NewReader(input))
更多信息请参考"Scanner terminating early"。
英文:
Considering that strings.Split() returns an array, it would be easier to use range
m := strings.Split(metrics.String(), "\n")for _, m := range strings.Split(metrics.String(), "\n") {log.Printf("metric: %s", m)}
Note, to read lines from a string, you can consider "go readline -> string":
bufio.ReadLine() or better: bufio.Scanner
As in:
const input = "Now is the winter of our discontent,\nMade glorious summer by this sun of York.\n"scanner := bufio.NewScanner(strings.NewReader(input))
See more at "Scanner terminating early".
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