英文:
Set a parameter as an interface or a list of interfaces
问题
我对Go还不太熟悉，还有一些细微之处我还不太理解。
例如，我有一个函数可能会这样调用：
myVar.InitOperation("foo", Operator.EQUAL, "bar")
myVar.InitOperation("foo", Operator.INCLUDE, []interface{}{"baz", 1, "boo"})
myVar.InitOperation("foo", Operator.GREATER_THAN, 1)
所以我将这个函数声明为：
func InitOperation(attr string, operator Operator, value interface{}) {
if operator.String() == "BAR" {
doSomething(attr, operator, value)
} else if operator.String() == "INCLUDE" {
doSomethingElse(attr, operator, value)
}
// 根据情况继续处理
}
问题是，当我传递一个字符串或整数时，一切都正常，但当我传递一个数组时，它被解析为单个元素。
在我的函数doSomethingElse中，我尝试迭代values，正如你可能猜到的，我遇到了错误。
好吧，我只需将values设置为[]interface{}而不是interface{}。在这里，一切都正常，但当我调用doSomething时，它被解析为[[myValue]]，这是合理的，但不是我期望的。
我的问题是，有没有办法根据情况传递[]interface{}或interface{}，以便根据情况将其解析为值或值数组？
谢谢！
英文:
I'm pretty new to Go and there are some subtilities that I don't get yet
For instance, I have a function who may be called like this :
myVar.InitOperation("foo",Operator.EQUAL,"bar")
myVar.InitOperation("foo",Operator.INCLUDE,[]interface{}{"baz",1,"boo"})
myVar.InitOperation("foo",Operator.GREATER_THAN,1)
So I declared this function as :
func InitOperation(attr string, operator Operator, value interface{}){
if operator.String() == "BAR"{
doSomething(attr,operator,value)
} else if (operator.String() == "INCLUDE" {
doSomethingElse(attr,operator,value)
}
// And so on regarding to the case
}
The thing is that when I pass a string or an integer, it goes well but when I pass an array, it is parsed as a single element.
In my function doSomethingElse, I'm trying to iterate over values, and as you may guess, I have an error.
Fine, I'll just set values as []interface{} and not interface{}. Here, everything goes well but when I'm calling doSomething, it is parsed as [[myValue]] which is logical but not what I expect.
My question is, is there a way to pass either an []interface{} or interface{} who can be red as a value or an array of values regarding to the case ?
Thanks !
答案1
得分: 2
你需要进行类型断言：
func InitOperation(attr string, operator Operator, value interface{}) {
if operator.String() == "BAR" {
doSomething(attr, operator, value)
} else if operator.String() == "INCLUDE" {
doSomethingElse(attr, operator, value.([]interface{}))
}
// 根据情况继续处理
}
func doSomethingElse(attr string, operator Operator, value []interface{}) {
for _, v := range value {
fmt.Println(v)
}
}
在 InitOperation 函数中，根据 operator 的不同值，调用不同的函数进行处理。当 operator 的值为 "BAR" 时，调用 doSomething 函数；当 operator 的值为 "INCLUDE" 时，调用 doSomethingElse 函数，并将 value 进行类型断言为 []interface{} 类型。在 doSomethingElse 函数中，遍历 value 数组并打印每个元素。
英文:
You need a type assertion:
func InitOperation(attr string, operator Operator, value interface{}){
if operator.String() == "BAR"{
doSomething(attr,operator,value)
} else if (operator.String() == "INCLUDE" {
doSomethingElse(attr, operator, value.([]interface{}))
}
// And so on regarding to the case
}
func doSomethingElse(attr string, operator Operator, value []interface{}) {
for _, v := range value {
fmt.Println(v)
}
}
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