How do you perform a deep copy of a ternary tree in Go?

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英文:

How do you perform a deep copy of a ternary tree in Go?

问题

我正在尝试对以下结构体执行深拷贝:

// 三叉树
type Tree struct {
Left *Tree
Mid *Tree
Right *Tree
Value interface{}
Parent *Tree
Orientation string
IsTerminal bool
Type string
}

以下是我尝试的代码。看起来我在根节点创建了一个新的树,但它的子节点仍然指向相同的内存地址。

func (tree *Tree) CopyTree() *Tree {
if (tree == nil) {
return nil
} else {
copiedTree := &Tree {
tree.Left.CopyTree(),
tree.Mid.CopyTree(),
tree.Right.CopyTree(),
tree.Value,
tree.Parent.CopyTree(),
tree.Orientation,
tree.IsTerminal,
tree.Type}
return copiedTree
}
}

Go语言中是否有任何有用的构造来辅助深拷贝一个结构体?如果没有,我该如何自己执行这个深拷贝?请注意,"deepcopy"包在Go 1发布时使用了一些已被弃用的函数,因此不再可用。

英文:

I'm attempting to perform a deep copy of the following struct:

// Ternary Tree
type Tree struct {
    Left  *Tree
    Mid *Tree
    Right *Tree
    Value interface{}
    Parent *Tree
    Orientation string
    IsTerminal bool
    Type string
}

The following is my sorry attempt. It looks like I'm creating a new tree at the root but it's children are still pointing to the same address in memory.

func (tree *Tree) CopyTree() *Tree {
    if (tree == nil) {
        return nil
    } else {
        copiedTree := &Tree {
            tree.Left.CopyTree(),
            tree.Mid.CopyTree(),
            tree.Right.CopyTree(),
            tree.Value,
            tree.Parent.CopyTree(),
            tree.Orientation,
            tree.IsTerminal,
            tree.Type}
        return copiedTree
    }
}

Are there any useful constructs in go that assist with deep copying a struct? If not, how would I perform this deep copy myself? Note, the "deepcopy" package no longer works as it uses a few functions that were deprecated with the release of Go 1

答案1

得分: 10

我离成功很近了。我应该将copiedTree赋值给parent属性。

func (tree *Tree) CopyTree() *Tree {
    if (tree == nil) {
        return nil
    } else {
        copiedTree := &Tree {
            tree.Left.CopyTree(),
            tree.Mid.CopyTree(),
            tree.Right.CopyTree(),
            tree.Value,
            nil,
            tree.Orientation,
            tree.IsTerminal,
            tree.Type,
        }
    
        if copiedTree.Left != nil {
            copiedTree.Left.Parent = copiedTree
        }
        if copiedTree.Right != nil {
            copiedTree.Right.Parent = copiedTree
        }
        if copiedTree.Mid != nil {
            copiedTree.Mid.Parent = copiedTree
        }
        return copiedTree
    }
}
英文:

I was close. I should have assigned the copiedTree to the parent property.

func (tree *Tree) CopyTree() *Tree {
    if (tree == nil) {
        return nil
    } else {
        copiedTree := &Tree {
            tree.Left.CopyTree(),
            tree.Mid.CopyTree(),
            tree.Right.CopyTree(),
            tree.Value,
            nil,
            tree.Orientation,
            tree.IsTerminal,
            tree.Type,
        }
    
        if copiedTree.Left != nil {
            copiedTree.Left.Parent = copiedTree
        }
        if copiedTree.Right != nil {
            copiedTree.Right.Parent = copiedTree
        }
        if copiedTree.Mid != nil {
            copiedTree.Mid.Parent = copiedTree
        }
        return copiedTree
    }
}

答案2

得分: 0

你可以通过encoding/gob来进行往返转换:

package main

import (
   "bytes"
   "encoding/gob"
)

func copyStruct(in, out interface{}) {
   buf := new(bytes.Buffer)
   gob.NewEncoder(buf).Encode(in)
   gob.NewDecoder(buf).Decode(out)
}

func main() {
   type date struct { Month, Day int }
   a := date{12, 31}
   var b date
   copyStruct(a, &b)
}

https://golang.org/pkg/encoding/gob

英文:

You can roundtrip it through encoding/gob:

package main

import (
   "bytes"
   "encoding/gob"
)

func copyStruct(in, out interface{}) {
   buf := new(bytes.Buffer)
   gob.NewEncoder(buf).Encode(in)
   gob.NewDecoder(buf).Decode(out)
}

func main() {
   type date struct { Month, Day int }
   a := date{12, 31}
   var b date
   copyStruct(a, &b)
}

https://golang.org/pkg/encoding/gob

答案3

得分: -1

json.Marshal和json.Unmarshal怎么样?如果性能很重要,我更倾向于使用protobuf。

英文:

How about json.Marshal and json.Unmarshal. If performance is critical, I perfer to use protobuf.

huangapple
  • 本文由 发表于 2014年10月28日 07:24:38
  • 转载请务必保留本文链接:https://go.coder-hub.com/26598524.html
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