英文:
Reduce array length
问题
尝试将两个字符串数组合并为一个数组。结果数组应该删除所有重复的元素。
func MergeArrays(str1, str2 []string) []string {
c := make([]string, len(str1)+len(str2), cap(str1)+cap(str2))
k := make(map[string]bool)
for i, s := range str1 {
if _, ok := k[s]; !ok {
c[i] = s
k[s] = true
}
}
for j, s := range str2 {
if _, ok := k[s]; !ok {
c[j+len(str1)] = s
k[s] = true
}
}
return c
}
测试数据
str1 := []string{"a", "b"}
str2 := []string{"c", "d", "a"}
输出：
"a", "b", "c", "d"
数组的长度为5
我得到了我想要的输出，但数组的长度应该是4而不是5。我可以理解为什么会打印5，但我希望输出的数组长度为4。
是否有其他方法可以合并两个数组？
英文:
Am trying to merge two string array to one. The resulting array should have all duplicates element removed.
func MergeArrays(str1, str2 []string) []string {
c := make([]string, len(str1)+len(str2), cap(str1)+cap(str2))
k := make(map[string]bool)
for i, s := range str1 {
if _, ok := k展开收缩; !ok {
c[i] = s
k展开收缩 = true
}
}
for j, s := range str2 {
if _, ok := k展开收缩; !ok {
c[j+len(str1)] = s
k展开收缩 = true
}
}
return c
}
Test Data
str1 := []string{"a", "b"}
str2 := []string{"c", "d", "a"}
Output:
"a", "b", "c", "d"
length of the array "5"
Am getting the output i want, but the length of the array should be 4 and not 5. I can understand why it prints 5, but i want the output array of length 4.
Is there other way to merge two arrays.
答案1
得分: 2
它们是切片，而不是数组，这里有一个示例可以解决你的用例：
package main
import "fmt"
func MergeStringSlices(str1, str2 []string) []string {
m := make([]string, len(str1), len(str1)+len(str2))
copy(m, str1)
already_seen:
for _, s := range str2 {
for _, t := range m {
if s == t {
continue already_seen
}
}
m = append(m, s)
}
return m
}
func main() {
str1 := []string{"a", "b"}
str2 := []string{"c", "d", "a"}
fmt.Printf("%#v\n", MergeStringSlices(str1, str2))
}
英文:
They're slices, not arrays and here's an example that solves your use-case:
package main
import "fmt"
func MergeStringSlices(str1, str2 []string) []string {
m := make([]string, len(str1), len(str1)+len(str2))
copy(m, str1)
already_seen:
for _, s := range str2 {
for _, t := range m {
if s == t {
continue already_seen
}
}
m = append(m, s)
}
return m
}
func main() {
str1 := []string{"a", "b"}
str2 := []string{"c", "d", "a"}
fmt.Printf("%#v\n", MergeStringSlices(str1, str2))
}
答案2
得分: 2
从零开始，当你添加一个元素时，长度加一。例如，
package main
import "fmt"
func MergeArrays(a1, a2 []string) []string {
m := make([]string, 0, len(a1)+len(a2))
k := make(map[string]bool, len(a1)+len(a2))
for _, aa := range [][]string{a1, a2} {
for _, s := range aa {
if !k[s] {
m = append(m, s)
k[s] = true
}
}
}
return m
}
func main() {
a1 := []string{"a", "b"}
a2 := []string{"c", "d", "a"}
m := MergeArrays(a1, a2)
fmt.Println(len(m), m)
}
输出结果：
4 [a b c d]
英文:
Start with a length of zero and add one when you append an element. For example,
package main
import "fmt"
func MergeArrays(a1, a2 []string) []string {
m := make([]string, 0, len(a1)+len(a2))
k := make(map[string]bool, len(a1)+len(a2))
for _, aa := range [][]string{a1, a2} {
for _, s := range aa {
if !k展开收缩 {
m = append(m, s)
k展开收缩 = true
}
}
}
return m
}
func main() {
a1 := []string{"a", "b"}
a2 := []string{"c", "d", "a"}
m := MergeArrays(a1, a2)
fmt.Println(len(m), m)
}
Output:
4 [a b c d]
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