英文:
Golang use function that returns two variable
问题
假设有一个返回两个变量的函数。
func num(a, b int) (int, int) {return a + b, a - b}
假设我有一个只接受一个整数值的函数。
package mainimport "fmt"func main() {fmt.Println("Hello, playground")_, a := num(1, 2)prn(a)}func num(a, b int) (int, int) {return a + b, a - b}func prn(a int) {fmt.Println(a)}
有没有办法在不使用_, a := num(1, 2)的情况下只获取第二个值（a-b）？类似于prn(num(1, 2)[1])这样的方式，这种方式不起作用，但我想知道是否有类似的方法。
谢谢。
英文:
Assume there is a function that returns two variables.
func num(a,b int) (int,int) {return a+b, a-b}
http://play.golang.org/p/bx05BugelV
And assume I have a function that only takes one int value.
package mainimport "fmt"func main() {fmt.Println("Hello, playground")_, a := num(1, 2)prn(a)}func num(a, b int) (int, int) {return a + b, a - b}func prn(a int) {fmt.Println(a)}
http://play.golang.org/p/VhxF_lbVf4
Is there anyway I can only get the 2nd value (a-b) without having _,a:=num(1,2)??
Something like prn(num(1,2)[1]) <-- this won't work, but I'm wondering if there's a similar way
Thank you
答案1
得分: 3
使用一个包装函数。例如，
package mainimport "fmt"func main() {_, a := num(1, 2)prn(a)prn1(num(1, 2))}func num(a, b int) (int, int) {return a + b, a - b}func prn(a int) {fmt.Println(a)}func prn1(_, b int) {prn(b)}
输出：
-1-1
英文:
Use a wrapper function. For example,
package mainimport "fmt"func main() {_, a := num(1, 2)prn(a)prn1(num(1, 2))}func num(a, b int) (int, int) {return a + b, a - b}func prn(a int) {fmt.Println(a)}func prn1(_, b int) {prn(b)}
Output:
-1-1
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