英文:
Programmatically writing stdin for an os.Process
问题
更新：要以编程方式“驱动”bash，您需要一个伪终端（PTY）。这就是我正在寻找的：
https://github.com/kr/pty
package main
import (
"github.com/kr/pty"
"io"
"os"
"os/exec"
)
func main() {
c := exec.Command("grep", "--color=auto", "bar")
f, err := pty.Start(c)
if err != nil {
panic(err)
}
go func() {
f.Write([]byte("foo\n"))
f.Write([]byte("bar\n"))
f.Write([]byte("baz\n"))
f.Write([]byte{4}) // EOT
}()
io.Copy(os.Stdout, f)
}
给定以下示例：
package main
import (
"fmt"
"os"
)
func main() {
attr := &os.ProcAttr{
Files: []*os.File{os.Stdin, os.Stdout, os.Stderr},
}
process, err := os.StartProcess("/bin/bash", nil, attr)
if err != nil {
fmt.Printf("process err %v\n", err)
return
}
state, err := process.Wait()
if err != nil {
fmt.Printf("wait err %v\n", err)
}
fmt.Printf("'%+v'\n", state)
}
我可以按预期运行bash：
go run proc.go
bash-3.2$ echo foo
foo
bash-3.2$ exit
exit
'exit status 0'
然而，我想为os.Stdin指定自己的可写流，当我尝试传递一个文件（os.Open("/my/file")）时，进程将文件作为stdin并在io.EOF处退出。如何创建一个“无限长”的可写文件？通过查看文档，似乎我需要以某种方式使用os.OpenFile...
英文:
Update: To programmatically "drive" bash, you need a Pseudo terminal (PTY).This is what I looking for:
https://github.com/kr/pty
package main
import (
"github.com/kr/pty"
"io"
"os"
"os/exec"
)
func main() {
c := exec.Command("grep", "--color=auto", "bar")
f, err := pty.Start(c)
if err != nil {
panic(err)
}
go func() {
f.Write([]byte("foo\n"))
f.Write([]byte("bar\n"))
f.Write([]byte("baz\n"))
f.Write([]byte{4}) // EOT
}()
io.Copy(os.Stdout, f)
}
Given the following example:
package main
import (
"fmt"
"os"
)
func main() {
attr := &os.ProcAttr{
Files: []*os.File{os.Stdin, os.Stdout, os.Stderr},
}
process, err := os.StartProcess("/bin/bash", nil, attr)
if err != nil {
fmt.Printf("process err %v\n", err)
return
}
state, err := process.Wait()
if err != nil {
fmt.Printf("wait err %v\n", err)
}
fmt.Printf("'%+v'\n", state)
}
I can run bash as expected:
go run proc.go
bash-3.2$ echo foo
foo
bash-3.2$ exit
exit
'exit status 0'
However, I'd like to specify my own writable stream for os.Stdin and when I try passing it a file (os.Open("/my/file")), the process takes the file as stdin and exits at io.EOF. How can I create an "infinitely long" writable file?
Looking through the docs it seems I'd need to use os.OpenFile in some way...
答案1
得分: 2
你无法这样做。但是，你可以创建一个 os.Pipe() 并将文件推送到其中一侧。只要不关闭管道，它就会无限进行下去。
英文:
You can't. However, you can create an os.Pipe() and push your file to one side. It will be inifinite as long as you do not close the pipe.
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