英文:
Interface pointer as a function argument
问题
这很可能源于对Go语言中interface{}的误解。以下是你的代码:
type Configuration struct {
Username string
}
func loadJson(jsonStr []byte, x *Configuration}) {
json.Unmarshal(jsonStr, x)
}
func main() {
//var config *Configuration
config := new(Configuration)
file, e := ioutil.ReadFile("config.json")
loadJson(file, config)
fmt.Printf("%s\n", config.Username)
}
它将一个JSON配置加载到config变量中。我想让loadJson函数更抽象,接受任何结构体。我认为最好的方法是接受*interface{}
,但是当我改变loadJson的签名时,我得到了以下错误:
./issue.go:30: cannot use config (type *Configuration) as type *interface {} in argument to loadJson:
*interface {} is pointer to interface, not interface
相反,loadJson应该是这样的:
func loadJson(jsonStr []byte, x interface{}) {
json.Unmarshal(jsonStr, x)
}
interface{}已经是一个指针吗?另外,错误消息对我来说并不是很清楚,难道Configuration不是指向接口的指针吗?另外,如果我将json.Unmarshal(jsonStr, x)
更改为json.Unmarshal(jsonStr, &x)
,它仍然可以正常工作。这是怎么回事?
另外一个相关的问题是关于指针的,为什么我不能像main函数中的注释行那样声明一个指针呢?
英文:
This most likely stems from a misunderstanding of what interface{} is in go. I have the following code
type Configuration struct {
Username string
}
func loadJson(jsonStr []byte, x *Configuration}) {
json.Unmarshal(jsonStr, x)
}
func main() {
//var config *Configuration
config := new(Configuration)
file, e := ioutil.ReadFile("config.json")
loadJson(file, config)
fmt.Printf("%s\n", config.Username)
}
It loads a json configuration into the config variable. I want to make the loadJson function more abstract and accept any struct. I thought the best way to do that would be to accept a *interface{}
, however I get the following error when changing the loadJson Signature.
./issue.go:30: cannot use config (type *Configuration) as type *interface {} in argument to loadJson:
*interface {} is pointer to interface, not interface
Instead load json should be this
func loadJson(jsonStr []byte, x interface{}}) {
json.Unmarshal(jsonStr, x)
}
Is interface{} already a pointer? Also the error message doesn't make the most sense to me, isn't configuration a pointer to an interface? Also, if I change json.Unmarshal(jsonStr, x)
to json.Unmarshal(jsonStr, &x)
it will work perfectly fine still. What is going on here that allows that to work?
Side question but relevant to pointers, why can't I declare a pointer like the commented out line(under main)?
答案1
得分: 4
使用interface{}来表示任何类型,包括指针:
func loadJson(jsonStr []byte, x interface{}) {
json.Unmarshal(jsonStr, x)
}
虽然你可以将Configuration
赋值给interface{}
,但是Configuration
值和interface{}
值的内存布局是不同的。由于内存布局不同,无法将interface{}
的指针转换为Configuration
的指针。同样的原因也适用于[]T
和[]interface{}
。
在Go语言中很少使用指向接口的指针。
关于附注:你可以使用变量声明和赋值:
var config *Configuration
config = new(Configuration)
或者你可以使用短变量声明:
config := new(Configuration)
你不能同时使用声明和短变量声明,因为这会导致变量声明两次。
英文:
Use interface{} to represent any type including pointers:
func loadJson(jsonStr []byte, x interface{}) {
json.Unmarshal(jsonStr, x)
}
<kbd>playground</kbd>
Although you can assign a Configuration
to an interface{}
, the memory layout of a Configuration
value and an interface{}
value are different. Because the memory layouts are different, a pointer to an interface{}
cannot be converted to a pointer to a Configuration
. The same reasoning applies to a []T
and a []interface[}
.
It's rare to user a pointer to an interface in Go.
Regarding the side note: You can use a variable declaration and assignment
var config *Configuration
config = new(Configuration)
or you can use a short variable declaration:
config := new(Configuration)
You cannot use declaration and short declaration together because it declares the variable twice.
答案2
得分: 2
interface{}
是一个特殊的类型,它可以表示任意类型的值。在Go语言中,接口类型是一种多态的实现方式。当一个值实现了某个接口时,它可以被包装在该接口类型的变量中。
在代码中,*Configuration
和*interface{}
都是指针类型,但它们是完全不同的类型。即使它们在内存中的表示方式可能相同,你也不能将*int
赋值给*interface{}
,因为它们是不兼容的类型。
关于为什么interface{}
可以接受任意类型的值,这是因为接口类型在实现上有所特殊。在接口类型中,值可以被“装箱”成接口值,只要它实现了该接口。
需要注意的是,接口值在底层有时会持有一个指针,但这是实现细节,在这里并不相关。
参考链接:http://play.golang.org/p/EbGCn8F7op
英文:
> Is interface{} already a pointer?
No, not in general <sup>[1]</sup>.
> What is going on here that allows that to work?
Consider the following type definition:
type Number int
int
and Number
are now two completely distinct types. You can't use a *int
where a *Number
is expected; even if they are essentially the same, even memory-wise.
The rule is the same for *Configuration
and *interface{}
; even if their memory representation was identical (which it isn't).
Why does it work for interface{}
then? Because interface-types are special; they are Go's way of doing polymorphism. Any value can be "boxed" in an interface value if it implements said interface.
<sup>[1] Under the hood, an interface value sometimes holds a pointer but that's an implementation detail and not relevant here.</sup>
答案3
得分: 1
一个指向接口的指针与一个指向配置的指针具有不同的内存布局。它们不能互换使用,你不能使用*interface{}来表示任何指针。将接口值想象成一个盒子。你想要将json函数传递一个包含指针的盒子,而不是一个指向盒子的指针。
如果你想要了解接口的底层表示,请参考http://research.swtch.com/interfaces。
英文:
A pointer to an interface has a different memory layout than a pointer to a Configuration. They are not interchangeable and you can't use *interface{} to represent any pointer. Think of an interface value like a box. The idea is you want to pass the json function a box containing a pointer and not a pointer to a box.
If you want to understand the underlying representation of an interface, see http://research.swtch.com/interfaces.
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