Go unmarshal xml into struct

huangapple
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英文:

Go unmarshal xml into struct

问题

我有这个xml文件，似乎无法将任何数据解组到结构体中。有人可以在这里帮助我吗？我以前从未使用过xml，总是更喜欢json。我刚刚用我的代码编辑了这篇帖子，但它仍然给我空的结构体值。

  1. <Envelope>
  2. 	<Data>
  3. 		<Order>
  4. 			<DeliveryData>
  5. 				<del_country>BELGIQUE/BELGIE</del_country>
  6. 				<del_country_code>BE</del_country_code>
  7. 				<del_company>False</del_company>
  8. 				<del_name>ADAM</del_name>
  9. 				<del_contact></del_contact>
  10. 				<del_firstName></del_firstName>
  11. 				<del_addressLine1>Durasweg 33</del_addressLine1>
  12. 				<del_addressLine2></del_addressLine2>
  13. 				<del_areaCode>1000</del_areaCode>
  14. 				<del_city>BRUXELLES</del_city>
  15. 				<del_country>BE</del_country>
  16. 				<del_language>FR</del_language>
  17. 				<del_modeCode>71</del_modeCode>
  18. 				<phone1>0032872180808</phone1>
  19. 				<email></email>
  20. 				<inv_third>438802</inv_third>
  21. 				<OrderID>15787978</OrderID>
  22. 				<ParcelID>NE1578797801</ParcelID>
  23. 				<OrderDate>16/09/2014 14:22:54</OrderDate>
  24. 				<Shipping_date>16/09/2014 14:26:55</Shipping_date>
  25. 			</DeliveryData>
  26. 		</Order>
  27. 	</Data>
  28. </Envelope>
  1. type DeliveryData struct {
  2. 	XMLName xml.Name `xml:"DeliveryData"`
  3. 	Country string   `xml:"del_country"`
  4. }
  6. type Envelope struct {
  7. 	XMLName xml.Name `xml:"Envelope"`
  8. 	Data    Data     `xml:"Data"`
  9. }
  11. type Data struct {
  12. 	XMLName xml.Name `xml:"Data"`
  13. 	Orders  []Order  `xml:"Order"`
  14. }
  16. type Order struct {
  17. 	XMLName      xml.Name     `xml:"Order"`
  18. 	DeliveryData DeliveryData `xml:"DeliveryData"`
  19. }
英文:

I have this xml file and i it seems i cant unmarshal any data into a struct. Someone can help me out here. Its just i never used xml before, always prefered json before xml. Just edited this post with my code and it still gives me empty struct values

  1. &lt;Envelope&gt;
  2. &lt;Data&gt;
  3. 		&lt;Order&gt;
  4. 			&lt;DeliveryData&gt;
  5. 				&lt;del_country&gt;BELGIQUE/BELGIE&lt;/del_country&gt;
  6. 				&lt;del_country_code&gt;BE&lt;/del_country_code&gt;
  7. 				&lt;del_company&gt;False&lt;/del_company&gt;
  8. 				&lt;del_name&gt;ADAM&lt;/del_name&gt;
  9. 				&lt;del_contact&gt;&lt;/del_contact&gt;
  10. 				&lt;del_firstName&gt;&lt;/del_firstName&gt;
  11. 				&lt;del_addressLine1&gt;Durasweg 33&lt;/del_addressLine1&gt;
  12. 				&lt;del_addressLine2&gt;&lt;/del_addressLine2&gt;
  13. 				&lt;del_areaCode&gt;1000&lt;/del_areaCode&gt;
  14. 				&lt;del_city&gt;BRUXELLES&lt;/del_city&gt;
  15. 				&lt;del_country&gt;BE&lt;/del_country&gt;
  16. 				&lt;del_language&gt;FR&lt;/del_language&gt;
  17. 				&lt;del_modeCode&gt;71&lt;/del_modeCode&gt;
  18. 				&lt;phone1&gt;0032872180808&lt;/phone1&gt; 
  19. 				&lt;email&gt;&lt;/email&gt;
  20. 				&lt;inv_third&gt;438802&lt;/inv_third&gt;
  21. 				&lt;OrderID&gt;15787978&lt;/OrderID&gt;
  22. 				&lt;ParcelID&gt;NE1578797801&lt;/ParcelID&gt;
  23. 				&lt;OrderDate&gt;16/09/2014 14:22:54&lt;/OrderDate&gt;
  24. 				&lt;Shipping_date&gt;16/09/2014 14:26:55&lt;/Shipping_date&gt;
  25. 			&lt;/DeliveryData&gt;
  26. 	&lt;/Order&gt;
  27.   &lt;/Data&gt;

</Envelope>

  1.  type DeliveryData struct {
  2. 	XMLName xml.Name `xml:&quot;DeliveryData&quot;`
  3. 	Country string   `xml:&quot;del_country&quot;`
  4. }
  6. type Envelope struct {
  7. 	XMLName xml.Name `xml:&quot;Envelope&quot;`
  8. 	Data    Data     `xml:&quot;Data&quot;`
  9. }
  11. type Data struct {
  12. 	XMLName xml.Name `xml:Data`
  13. 	Orders  []Order  `xml:Order`
  14. }
  16. type Order struct {
  17. 	XMLName      xml.Name     `xml:&quot;Order&quot;`
  18. 	DeliveryData DeliveryData `xml:&quot;DeliveryData&quot;`
  19. }

答案1

得分: 7

有两个原因：

  1. 你的 XML 格式不正确 - 你应该添加一个闭合的 &lt;/Envelope&gt;。
  2. 你在 Data 结构体标签中的格式不正确 - 它们没有引用属性的名称 - 这意味着 XML 反序列化器会寻找一个名为 'Order' 的字段，而不是 Orders 字段。

为了确保正确：你可以在 http://play.golang.org/p/6-odOcSOnF 找到一个完整可工作的示例。

相关部分是我的

  1. type Data struct {
  2.     XMLName xml.Name `xml:&quot;Data&quot;`
  3.     Orders  []Order  `xml:&quot;Order&quot;`
  4. }

与你原来的

  1. type Data struct {
  2.     XMLName xml.Name `xml:Data`
  3.     Orders  []Order  `xml:Order`
  4. }
英文:

There are two reasons:

  1. Your XML is malformed - you should add a closing &lt;/Envelope&gt;.
  2. Your struct tags in Data are malformed – they don't quote the name of the attribute - this means the the XML deserializer looks for an 'Order' field, instead of the Orders field.

For good measure: you can find a fully working example on http://play.golang.org/p/6-odOcSOnF

The relevant part is my

  1. type Data struct {
  2.     XMLName xml.Name `xml:&quot;Data&quot;`
  3.     Orders  []Order  `xml:&quot;Order&quot;`
  4. }

versus your original

  1. type Data struct {
  2.     XMLName xml.Name `xml:Data`
  3.     Orders  []Order  `xml:Order`
  4. }

答案2

得分: 0

根据@publysher的回答，你实际上不需要那么多的结构体，只需要两个：

  1. type Data struct {
  2.     XMLName xml.Name       `xml:"Envelope"`
  3.     Data    []Fields `xml:"Data>Order>DeliveryData"`
  4. }
  6. type Fields struct {
  7.     Country string   `xml:"del_country"`
  8.     OrderID uint64
  9. }

然后你可以解析你的XML（在你修复它之后，就像@publysher指出的那样）：

  1. var data Data
  2. err := xml.Unmarshal([]byte(serialized), &data)
  3. if err != nil {
  4.     fmt.Println(err)
  5.     return
  6. }
英文:

Adding to @publysher's answer, you don't actually need to have so many structs, you just need 2:

  1. type Data struct {
  2. 	XMLName xml.Name       `xml:&quot;Envelope&quot;`
  3. 	Data  []Fields `xml:&quot;Data&gt;Order&gt;DeliveryData&quot;`
  4. }
  6. type Fields struct {
  7. 	Country string   `xml:&quot;del_country&quot;`
  8. 	OrderID uint64
  9. }

then you can unmarshal your xml (after you fix it of course like @publysher pointed out):

  1. var data Data
  2. err := xml.Unmarshal([]byte(serialized), &amp;data)
  3. if err != nil {
  4. 	fmt.Println(err)
  5. 	return
  6. }

huangapple
  • 本文由 发表于 2014年10月13日 16:21:07
  • 转载请务必保留本文链接：https://go.coder-hub.com/26335607.html
  • go
  • xml
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