Getting Content-Type header for uploaded files processed using net/http request.ParseMultipartForm

I'm using the net/http package to write a server that, among other things, receives a files uploaded via POST with the multipart/form-data encoding.

Working my way through the net/http docs, I've managed to write a function that calls the ParseMultipartForm method on the request and then interrogates the MultipartForm field for the file data, but I seem to be stuck on how to get the Content Type of the individual files uploaded as part of the post request -- all the ContentType related references in the source of request.go seem to be related to getting the multipart/form encoding, and when I printf-dump the uploaded file information, I don't seem to see any types, fields, or map keys that look content type related.

Here's what I've got right now that's doing the work of the file upload:

func save_multipart_upload(r *http.Request, savepath string) ([]string, error) {
fmt.Println("CALL: save_multipart_upload(r,"+savepath+")")
var savedfiles []string
err := r.ParseMultipartForm(100000)
if err != nil {
return savedfiles, err
}
m := r.MultipartForm
fmt.Printf("MPF: %#v \n", m)
for fname, _ := range r.MultipartForm.File {
files := m.File[fname]
fmt.Printf("files: %#v \n", m)
for i, _ := range files {
//for each fileheader, get a handle to the actual file
file, err := files[i].Open()
fmt.Printf("file: %#v \n", file)
defer file.Close()
if err != nil {
return savedfiles, err
}
//create destination file making sure the path is writeable.
var filename string
if savepath[:len(savepath)] == "/" {
filename = savepath + files[i].Filename
} else {
filename = savepath + "/" + files[i].Filename
}
dst, err := os.Create(filename)
if err != nil {
fmt.Println("Can't create "+filename+": "+err.Error())
return savedfiles, err
} else if _, err := io.Copy(dst, file); err != nil {
fmt.Println("Can't copy data %s: "+err.Error(), filename)
return savedfiles, err
} else {
fmt.Println("Saved %s successfully.", filename)
savedfiles = append(savedfiles, files[i].Filename)
}
}
}
/* end multipart upload */
fmt.Println("RETURN: receive_multipart_upload")
return savedfiles, err
}

And here's what I see from the print dumping if I pick a video file:

>CALL: save_multipart_upload(r,./static/000000000000000000000000/video/)
>
>MPF: &multipart.Form{Value:map[string][]string{}, File:map[string][]*multipart.FileHeader{"file1":[]*multipart.FileHeader{(*multipart.FileHeader)(0xc21004e580)}}}
>
>files: &multipart.Form{Value:map[string][]string{}, File:map[string][]*multipart.FileHeader{"file1":[]*multipart.FileHeader{(*multipart.FileHeader)(0xc21004e580)}}}
>
>file: &os.File{file:(*os.file)(0xc210079510)}
>
>Saved %s successfully. ./static/000000000000000000000000/video//2012-08-03 19.31.48.mov
>
>RETURN: receive_multipart_upload

multipart.FileHeader looks like it might be a clue, but when I drill down, that has a Header field, which is of type textproto.MIMEHeader, which basically looks like it's a map of strings to strings, so I still don't know what to look for.

Any ideas and sample code or suggested alterations to what I've got would be appreciated!

It should work like this:

m := r.MultipartForm
header := m.MIMEHeader
// Take a look at for instance 
// https://en.wikipedia.org/wiki/MIME#Multipart_messages
// You are looking for Content-Type...
// However, it can be multivalued. That's why you get a splice.
types, ok := header["Content-Type"]
if ok {
// This should be true!
for _, x := range types {
fmt.Printf("Content-Type: %v", x)
// Most usually you will probably see only one
}
}