英文:
Is there a built-in method to get a URL minus the query string?
问题
有没有内置的方法可以获取URL的部分，而不包括查询字符串？比如从http://example.com/?search=test中获取http://example.com/？
通过URL结构的字段组装（甚至可以通过问号字符进行分割）很容易实现，所以我不需要示例代码。这只是一个简单的问题，我想知道源代码/文档中是否有相关内容。谢谢！
英文:
Is there a built-in method to get the portion of a URL minus the query string? Like http://example.com/ from http://example.com/?search=test?
It's trivial to assemble from the fields of the URL struct (or even by splitting on the question mark char) so I'm not looking for sample code. This is just a simple question to see if it's there in the source/docs and I'm missing it. Thanks!
答案1
得分: 2
没有。没有适用于您的确切用例的便利函数。
但是，您可以使用net/url包来创建一个：
package main
import (
"fmt"
"log"
"net/url"
)
func main() {
result, err := url.Parse("http://example.com/?search=test?")
if err != nil {
log.Fatal("Invalid url", err)
}
fmt.Println(result.Scheme+"://"+result.Host+result.Path)
// or
result.RawQuery = ""
fmt.Println(result)
}
英文:
No. There is no convenience function for your exact use case.
but, you can use the net/url package to create one:
http://play.golang.org/p/Kk3EPBXMsm
package main
import (
"fmt"
"log"
"net/url"
)
func main() {
result, err := url.Parse("http://example.com/?search=test?")
if err != nil {
log.Fatal("Invalid url", err)
}
fmt.Println(result.Scheme+"://"+result.Host+result.Path)
// or
result.RawQuery = ""
fmt.Println(result)
}
答案2
得分: 0
对于其他正在寻找这些信息的人来说，正确的答案是否定的，没有内置的方法可以处理这个问题，可以按照我在问题中描述的方式处理，或者如上所示进行处理。
英文:
For others who are searching for this information, the correct answer is no, there isn't a built-in method for this, and it can be handled as I described in my question, or as demonstrated above.
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