英文:
go function input, func (req *AppendEntriesRequest) Encode(w io.Writer) (int, error) {
问题
func (req *AppendEntriesRequest) Encode(w io.Writer) (int, error) {
pb := &protobuf.AppendEntriesRequest{
Term: proto.Uint64(req.Term),
PrevLogIndex: proto.Uint64(req.PrevLogIndex),
PrevLogTerm: proto.Uint64(req.PrevLogTerm),
CommitIndex: proto.Uint64(req.CommitIndex),
LeaderName: proto.String(req.LeaderName),
Entries: req.Entries,
}
p, err := proto.Marshal(pb)if err != nil {return -1, err}return w.Write(p)
}
对于这个函数，"w" 是输入吗？req又是什么？有点困惑。
谢谢
英文:
func (req *AppendEntriesRequest) Encode(w io.Writer) (int, error) {pb := &protobuf.AppendEntriesRequest{Term: proto.Uint64(req.Term),PrevLogIndex: proto.Uint64(req.PrevLogIndex),PrevLogTerm: proto.Uint64(req.PrevLogTerm),CommitIndex: proto.Uint64(req.CommitIndex),LeaderName: proto.String(req.LeaderName),Entries: req.Entries,}p, err := proto.Marshal(pb)if err != nil {return -1, err}return w.Write(p)}
For this function, is "w" input? what about req? Kinda confused here.
Thanks
答案1
得分: 1
这是一个Go方法。
AppendEntriesRequest是一个类型，req *AppendEntriesRequest是该类型的指针。
在其他语言中，你可以将req与this或self进行比较。
w io.Writer是该函数的输入。
(int, error)是返回值。
你可以通过实例化一个AppendEntriesRequest结构来调用这个方法：
r := &AppendEntriesRequest{}n, err := r.Encode(...)
英文:
that is a Go Method
AppendEntriesRequest is a type and req *AppendEntriesRequest is a pointer to that type.
You can compare req in other languages as this or self
w io.Writer is the input of the function.
(int, error) are the return values.
You can invoke this method by instantiating a AppendEntriesRequest structure:
r := &AppendEntriesRequest{}n, err := r.Encode(...)
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