英文:
go function input, func (req *AppendEntriesRequest) Encode(w io.Writer) (int, error) {
问题
func (req *AppendEntriesRequest) Encode(w io.Writer) (int, error) {
pb := &protobuf.AppendEntriesRequest{
Term: proto.Uint64(req.Term),
PrevLogIndex: proto.Uint64(req.PrevLogIndex),
PrevLogTerm: proto.Uint64(req.PrevLogTerm),
CommitIndex: proto.Uint64(req.CommitIndex),
LeaderName: proto.String(req.LeaderName),
Entries: req.Entries,
}
p, err := proto.Marshal(pb)
if err != nil {
return -1, err
}
return w.Write(p)
}
对于这个函数,"w" 是输入吗?req又是什么?有点困惑。
谢谢
英文:
func (req *AppendEntriesRequest) Encode(w io.Writer) (int, error) {
pb := &protobuf.AppendEntriesRequest{
Term: proto.Uint64(req.Term),
PrevLogIndex: proto.Uint64(req.PrevLogIndex),
PrevLogTerm: proto.Uint64(req.PrevLogTerm),
CommitIndex: proto.Uint64(req.CommitIndex),
LeaderName: proto.String(req.LeaderName),
Entries: req.Entries,
}
p, err := proto.Marshal(pb)
if err != nil {
return -1, err
}
return w.Write(p)
}
For this function, is "w" input? what about req? Kinda confused here.
Thanks
答案1
得分: 1
这是一个Go方法。
AppendEntriesRequest
是一个类型,req *AppendEntriesRequest
是该类型的指针。
在其他语言中,你可以将req
与this
或self
进行比较。
w io.Writer
是该函数的输入。
(int, error)
是返回值。
你可以通过实例化一个AppendEntriesRequest
结构来调用这个方法:
r := &AppendEntriesRequest{}
n, err := r.Encode(...)
英文:
that is a Go Method
AppendEntriesRequest
is a type and req *AppendEntriesRequest
is a pointer to that type.
You can compare req
in other languages as this
or self
w io.Writer
is the input of the function.
(int, error)
are the return values.
You can invoke this method by instantiating a AppendEntriesRequest
structure:
r := &AppendEntriesRequest{}
n, err := r.Encode(...)
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