英文:
http.Server — get URL fragment
问题
无法使用标准的http.Server提取片段数据（foo在http://domain.com/path#foo中）。
package main
import (
"fmt"
"net/http"
)
type Handler struct {
}
func (handler Handler) ServeHTTP(w http.ResponseWriter, r *http.Request) {
fmt.Printf("Path = \"%v\" Fragment = \"%v\"\n", r.URL.Path, r.URL.Fragment)
}
func main() {
var handler Handler
http.ListenAndServe(":30000", handler)
}
对于http://127.0.0.1:30000/path#foo，会产生空的片段：
Path = "/path" Fragment = ""
如何使用Go语言的内置http.Server获取片段数据？
英文:
Have no luck with extracting fragment data (foo in http://domain.com/path#foo) with standard http.Server.
package main
import (
"fmt"
"net/http"
)
type Handler struct {
}
func (handler Handler) ServeHTTP(w http.ResponseWriter, r *http.Request) {
fmt.Printf("Path = \"%v\" Fragment = \"%v\"\n", r.URL.Path, r.URL.Fragment)
}
func main() {
var handler Handler
http.ListenAndServe(":30000", handler)
}
produces empty fragment for http://127.0.0.1:30000/path#foo:
Path = "/path" Fragment = ""
How can I get fragment data using golang's builtin http.Server?
答案1
得分: 16
你不能这样做。这不是Go的问题——URL片段不会通过HTTP发送到服务器。它们只是浏览器的概念。
这里有一个相关的问题，http.Request的文档已经更改为：
// 对于服务器请求，URL是从Request-Line中提供的URI解析而来的，该URI存储在RequestURI中。
// 对于大多数请求，除了Path和RawQuery之外的字段都将为空。（参见RFC 2616，第5.1.2节）
如果出于某种原因你需要它，你可以使用一些JavaScript将片段作为GET参数包含在请求中。
英文:
You can't. This isn't a Go thing -- URL fragments are not sent to the server over HTTP. They're just a browser concept.
Here is a relevant issue, where the docs for http.Request were changed to say:
// For server requests the URL is parsed from the URI
// supplied on the Request-Line as stored in RequestURI. For
// most requests, fields other than Path and RawQuery will be
// empty. (See RFC 2616, Section 5.1.2)
If for some reason you need it, you could probably string together some JavaScript to include the fragment in the request as a GET parameter or something.
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