Golang: execute text/template as bash script

Given the following:

   import(
   "bytes"
   "code.google.com/p/go/src/pkg/text/template"
   )

   ....

   var tmp = template.Must(template.New("").Parse(`
   echo {{.Name}}
   echo {{.Surname}}
   `[1:]))

   var buf bytes.Buffer
   tmp.Execute(&buf, struct{Name string, Surname: string}{"James","Dean"})
   bashScript = string(buf)
   
   // Now, how do I execute the bash script?
   magic.Execute(bashScript)

Is there a magic function that will execute the string as one bash script? "os/exec".Command can execute only one command at a time.

If you want to execute more than one command, especially more than one at a time, bash is not the best way to do that. Use os/exec and goroutines.

If you really want to run a bash script, here's an example using os/exec. I assumed you wanted to see the output of the bash script, rather than save it and process it (but you can easily do that with a bytes.Buffer). I've removed all the error checking here for brevity. The full version with error checking is here.

<pre>
package main

import (
"bytes"
"io"
"text/template"
"os"
"os/exec"
"sync"
)

func main() {
var tmp = template.Must(template.New("").Parse(
echo {{.Name}}
echo {{.Surname}}
[1:]))

    var script bytes.Buffer
    tmp.Execute(&script, struct {
            Name    string
            Surname string
    }{"James", "Dean"})

    bash := exec.Command("bash")
    stdin, _ := bash.StdinPipe()
    stdout, _ := bash.StdoutPipe()
    stderr, _ := bash.StderrPipe()

    wait := sync.WaitGroup{}
    wait.Add(3)
    go func () {
            io.Copy(stdin, &script)
            stdin.Close()
            wait.Done()
    }()
    go func () {
            io.Copy(os.Stdout, stdout)
            wait.Done()
    }()
    go func () {
            io.Copy(os.Stderr, stderr)
            wait.Done()
    }()

    bash.Start()
    wait.Wait()
    bash.Wait()

}
</pre>

Use bash -c... exec.Command("bash", "-c", bashScript).