Golang模板忽略没有匹配的情况。

huangapple go评论90阅读模式
英文:

Golang template ignore if no match

问题

我正在尝试转换一个 golang 模板,并允许在找不到匹配项时忽略。这可能吗?

package main

import (
	"bytes"
	"fmt"
	"text/template"
)

type Person struct {
	Name string
	Age  int
}

type Info struct {
	Name string
	Id   int
}

func main() {
	msg := "Hello {{ .Id }} With name {{ .Name }}"
	p := Person{Name: "John", Age: 24}
	i := Info{Name: "none", Id: 5}

	t := template.New("My template")
	t, _ = t.Parse(msg)

	buf := new(bytes.Buffer)
	t.Execute(buf, p)
	fmt.Println(buf.String())

	buf = new(bytes.Buffer)
	t.Execute(buf, i)
	fmt.Println(buf.String())
}

我希望输出结果为:

Hello {{ .Id }} with name John
Hello 5 With name none

英文:

I am trying to convert a golang template, and allow ignoring if the match is not found. Is that possible?

Playground

package main

import (
"bytes"
"fmt"
"text/template"
)
type Person struct {
Name string
Age  int
}
type Info struct {
Name string
Id   int
}

func main() {
msg := "Hello {{ .Id }} With name {{ .Name }}"
p := Person{Name: "John", Age: 24}
i := Info{Name: "none", Id: 5}

t := template.New("My template")
t, _ = t.Parse(msg)

buf := new(bytes.Buffer)
t.Execute(buf, p)
fmt.Println(buf.String())

buf = new(bytes.Buffer)
t.Execute(buf, i)
fmt.Println(buf.String())
}

I would like this to print

Hello {{ .Id }} with name John
Hello 5 With name none

答案1

得分: 1

如果你希望只在名称不为空字符串时打印名称:

"Hello {{ .Id }} With name {{ if .Name }}{{ .Name }}{{ end }}"

否则,如果你希望打印其他内容:

"Hello {{ .Id }} With name {{ if .Name }}{{ .Name }}{{ else }}none!{{ end }}"

Playground - 还可以查看html/template和text/template的比较运算符

英文:

If you want it to print name only when it's not an empty string:

"Hello {{ .Id }} With name {{ if .Name }}{{ .Name }}{{ end }}"

Else, if you want to it print something else:

"Hello {{ .Id }} With name {{ if .Name }}{{ .Name }}{{ else }}none!{{ end }}"

Playground - also see the comparison operators for html/template and text/template.

答案2

得分: 0

一个模板可以包含if语句,允许你执行你所需的操作。以下示例允许在提供了列表时显示列表,否则显示一条消息。

{{if .MyList}}
  {{range .MyList}}
    {{.}}
  {{end}}
{{else}}
  没有提供列表。
{{end}}

使用这种方法,我认为你可以实现你的需求。但是,由于你想保留未处理的{{.Id}},可能不太美观。

英文:

A template can contain if statements which allow you to do what you would need. The following example allows displaying a list if supplied, or when not supplied putting a message.

    {{if .MyList}}
      {{range .MyList}}
        {{.}}
      {{end}}
    {{else}}
      There is no list provided.
    {{end}}

Using this approach I think you can achieve what you need. But it might not be pretty as you want to leave the unprocessed {{.Id}} in place.

huangapple
  • 本文由 发表于 2014年8月1日 07:09:26
  • 转载请务必保留本文链接:https://go.coder-hub.com/25070414.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定