英文:
In Go, why does "File.Readdirnames" make a "clock_gettime" system call?
问题
作为对这个问题的后续，我正在尝试编写一个Go程序，以高效地列出文件名，而不进行不必要的系统调用。以下是我目前的代码：
package main
import (
"os"
"fmt"
"log"
)
func main() {
// 打开目录并检查错误
f, err := os.Open(".")
if err != nil {
log.Fatal(err)
}
// 获取文件名
files, err := f.Readdirnames(0)
if err != nil {
log.Fatal(err)
}
// 打印文件名
fmt.Print(files, "\n")
}
然而，当我运行strace时，我看到很多类似以下的输出：
clock_gettime(CLOCK_REALTIME, {1406822401, 824793686}) = 0
这是什么意思？我如何使这段代码更高效？
英文:
As a follow up to this question, I am trying to write a Go program that only lists a files name in an efficient matter without unnecessary system calls. This is what I have thus far:
package main
import (
"os"
"fmt"
"log"
)
func main() {
// Open directory and check for errors
f, err := os.Open(".")
if err != nil {
log.Fatal(err)
}
// Get file names
files, err := f.Readdirnames(0)
if err != nil {
log.Fatal(err)
}
// Print files
fmt.Print(files, "\n")
}
However, when I run an strace, I see many of the following:
clock_gettime(CLOCK_REALTIME, {1406822401, 824793686}) = 0
What does that pertain to? How can I make this code more efficient?
答案1
得分: 0
我正在翻译以下内容：
我只是随便猜测，但我认为这与Go的内置调度器和垃圾回收有关。
简而言之，由于Go提供了所有额外的运行时功能，它永远不会像C语言那样快。
你列出的代码可能是在Go中实现你想要的功能的最快方法。
英文:
I am spitballing, but I would think that it is related to Go's built-in scheduler and garbage collection.
Short answer is, go will never be quite as fast as C because it provides all of that extra runtime functionality which C doesn't.
The code you listed is probably the fastest way to do what you want in Go.
答案2
得分: -2
clock_gettime只是一个系统调用，在Go的运行时中被调用。运行时会做很多事情，比如调度等，所以有这么多的clock_gettime是正常的。
我认为你不能让这个程序更高效，因为它只是一个非常小的函数。你不应该在意这个。
英文:
clock_gettime is just a system call,which is called in go's runtime. runtime do a lot of things, schedual, and so on, so it's normal for so many clock_gettime.
I don't think you can make this program more efficient, 'cause it is just for so tiny function .You shouldn't mind it.
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