在Go语言中创建一个包含3个变量的映射(map):

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英文:

3 variable map in Go

问题

我正在尝试在Go语言中创建一个包含3个变量的映射,以便你可以执行类似以下的操作:

var postlist = make(map[int]map[int]bool)

postlist[postid][userid] = true

if postlist[postid][userid] == true {
   // 做一些操作
}

我尝试使用自定义结构体来创建映射,类似于:

var postlist = make(map[int]cusmap)

type cusmap struct {
    userid int
    seen   bool
}

但是我不知道如何同时检查userid和seen的条件。

英文:

I am trying to make a 3 variable map in go so that you can do something like.

var postlist = make(map[int][int]bool)

postlist[postid][userid] = true

if postid[postid][userid] = true {
   //do something
}

I have tried to make my own using a struct like

var postlist = make(map[int]cusmap)

type cusmap struct {
    userid     int
    seen       bool
}

but then I don't know how to check to check both the userid and seen bool condition.

答案1

得分: 5

我不确定你想要做什么,但是一个映射(map)只能是键/值对。你不能有键/键/值对。为了实现这个,你需要将值设置为一个映射,所以你可以这样做:

package main

func main() {
    var postlist = make(map[int]map[int]bool)

    postid, userid := 0, 0

    postlist[postid] = make(map[int]bool)
    postlist[postid][userid] = true

    if postlist[postid][userid] == true {
        println("ok")
    } else {
        println("ko")
    }
}

以上是一个示例代码,它创建了一个嵌套的映射,其中键是postid,值是一个映射,该映射的键是userid,值是一个布尔值。根据给定的postiduserid,你可以检查映射中的值是否为true

英文:

I am not sure what you are trying to do, but a map is only a key/value. You can't have key/key/value. In order to do this, you need the value to be a map, so you would do:

http://play.golang.org/p/dOAXNAI4CO

package main

func main() {
	var postlist = make(map[int]map[int]bool)

	postid, userid := 0, 0

	postlist[postid] = make(map[int]bool)
	postlist[postid][userid] = true

	if postlist[postid][userid] == true {
		println("ok")
	} else {
		println("ko")
	}
}

答案2

得分: 1

如果你想实现一组int对,你可以使用一个结构体作为映射的键:

type postData struct {
    userID int
    postID int
}

然后创建一个以postData为键,bool为值的映射:

postSet := map[postData]bool{
    postData{1234, 7284}: true,
    postData{7777, 1212}: true,
}

我们可以利用这样一个事实,即如果我们给映射一个不存在的索引,它将返回一个零值。
对于bool类型,零值是false

if postSet[postData{7777, 1212}] {
    fmt.Println("找到了帖子。")
} else {
    fmt.Println("没有这样的帖子!")
}

这里有一个完整的工作示例:http://play.golang.org/p/VJw9Vm8gHA

英文:

If you want to implement a set of int pairs, you can use a structure as the map key:

type postData struct {
	userID int
	postID int
}

Then make a map with postData keys and bool values:

postSet := map[postData]bool{
	postData{1234, 7284}: true,
	postData{7777, 1212}: true}

We can exploit the fact that if we give a non-existent index to the map, it will just return a zero-value.
For bool, the zero-value is false.

if postSet[postData{7777, 1212}] {
	fmt.Println("post found.")
} else {
	fmt.Println("no such post!")
}

Here's a full working example: http://play.golang.org/p/VJw9Vm8gHA

答案3

得分: 0

@creack的方法之外,还有一种方法是在地图本身上定义函数,这样你就不必每次手动检查是否要设置/取消某些东西:

func main() {
    cm := CustMap{}

    pid, uid := 0, 0

    cm.Set(pid, uid)

    fmt.Println(cm.Exists(pid, uid))
    fmt.Println(cm.Exists(pid, 10))
    fmt.Println(cm.Exists(10, 10))
}

type CustMap map[int]map[int]struct{} //struct使得地图在值方面使用0字节,而不是bools的1字节,当地图增长时很方便

func (cm CustMap) Set(pid, uid int) {
    if _, ok := cm[pid]; !ok {
        cm[pid] = make(map[int]struct{})
    }
    cm[pid][uid] = struct{}{}
}

func (cm CustMap) Exists(pid, uid int) (ok bool) {
    if u := cm[pid]; u != nil {
        _, ok = u[uid]
    }
    return
}

playground

英文:

An alternative to @creack's approach is to define funcs on the map itself that way you don't have to manually check every time you want to set / unset something:

func main() {
	cm := CustMap{}

	pid, uid := 0, 0

	cm.Set(pid, uid)

	fmt.Println(cm.Exists(pid, uid))
	fmt.Println(cm.Exists(pid, 10))
	fmt.Println(cm.Exists(10, 10))
}

type CustMap map[int]map[int]struct{} //struct makes the map use 0 bytes for values instead of 1 bytes for bools, handy as the map grows

func (cm CustMap) Set(pid, uid int) {
	if _, ok := cm[pid]; !ok {
		cm[pid] = make(map[int]struct{})
	}
	cm[pid][uid] = struct{}{}
}

func (cm CustMap) Exists(pid, uid int) (ok bool) {
	if u := cm[pid]; u != nil {
		_, ok = u[uid]
	}
	return
}

<kbd>playground</kbd>

huangapple
  • 本文由 发表于 2014年7月29日 03:11:39
  • 转载请务必保留本文链接:https://go.coder-hub.com/25002547.html
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