英文:
One struct with multiple json representations
问题
我正在尝试解决的问题是,我有一个类似于以下结构的社区模型:
type Community struct {
Name string
Description string
Sources []Source
Popularity int
FavoriteCount int
Moderators []string
Children []Community
Tracks []Track
}
社区包含很多信息,有时我只想返回部分描述,比如返回热门社区列表时。在这种情况下,我只想返回以下字段:
type Community struct {
Name string
Description string
Popularity int
FavoriteCount int
}
我能想到的唯一方法是创建一个新类型,只包含这些字段,并编写一个方便的方法,该方法接受一个社区对象并返回该类型。但本质上是创建一个新对象,并通过值复制这些字段,是否有更好的方法来实现这一点?
我知道可以使用json:"-"
语法,但我不确定如何根据情况进行操作,因为有时我仍然需要返回完整的对象。也许可以使用不同的类型进行转换?
英文:
The problem I'm trying to solve is that I have a model of a community that looks like this
type Community struct {
Name string
Description string
Sources []Source
Popularity int
FavoriteCount int
Moderators []string
Children []Community
Tracks []Track
}
Communities hold a lot of information and there are scenarios when I want to return only part of the description such as if I'm returning a list of trending communities. In this case I'd want to return only
type Community struct {
Name string
Description string
Popularity int
FavoriteCount int
}
The only way I can think of doing this is to create a new type containing only those fields and write a convenience method that takes a community and returns that type, but essentially creating a new object and copying those fields by value, is there a better way to do this?
I'm aware of the json:"-"
syntax, but I'm not sure of how you could do this on a case by case basis as I still need to sometimes return the full object, perhaps a different type that is converted to?
答案1
得分: 23
这是一个很酷的方法,它涉及创建一种类似掩码的结构。
以下是文章中的示例:
type User struct {
Email string `json:"email"`
Password string `json:"password"`
// 还有很多其他字段...
}
type omit *struct{}
type PublicUser struct {
*User
Password omit `json:"password,omitempty"`
}
// 当你想要编码你的用户时:
json.Marshal(PublicUser{
User: user,
})
英文:
This is a cool approach, which involves creating a sort of Masking struct.
Here's the example in the article:
type User struct {
Email string `json:"email"`
Password string `json:"password"`
// many more fields…
}
type omit *struct{}
type PublicUser struct {
*User
Password omit `json:"password,omitempty"`
}
// when you want to encode your user:
json.Marshal(PublicUser{
User: user,
})
答案2
得分: 5
是的,据我所知,使用默认的marshaler,这是唯一的方法。另外一个选项是创建自己的json.Marshaler。
type Community struct {
}
type CommunityShort Community
func (key *Community) MarshalJSON() ([]byte, os.Error) {
...
}
func (key *Community) UnmarshalJSON(data []byte) os.Error {
...
}
func (key *CommunityShort) MarshalJSON() ([]byte, os.Error) {
...
}
func (key *CommunityShort) UnmarshalJSON(data []byte) os.Error {
...
}
英文:
Yep that is the only way as far as I know using the default marshaler. The only other option is if you create your own json.Marshaler .
type Community struct {
}
type CommunityShort Community
func (key *Community) MarshalJSON() ([]byte, os.Error) {
...
}
func (key *Community) UnmarshalJSON(data []byte) os.Error {
...
}
func (key *CommunityShort) MarshalJSON() ([]byte, os.Error) {
...
}
func (key *CommunityShort) UnmarshalJSON(data []byte) os.Error {
...
}
答案3
得分: 5
我开发了一个可以帮助你的库:Sheriff
你可以使用特殊标签注释你的结构字段,并调用Sheriff将给定的结构转换为其子集。之后,你可以调用json.Marshal()
或其他你想要的编组方式。
你的示例将变得非常简单:
type Community struct {
Name string `json:"name" groups:"trending,detail"`
Description string `json:"description" groups:"trending,detail"`
Sources []Source `json:"sources" groups:"detail"`
Popularity int `json:"popularity" groups:"trending,detail"`
FavoriteCount int `json:"favorite_count" groups:"trending,detail"`
Moderators []string `json:"moderators" groups:"detail"`
Children []Community `json:"children" groups:"detail"`
Tracks []Track `json:"tracks" groups:"detail"`
}
communities := []Community{
// communities
}
o := sheriff.Options{
Groups: []string{"trending"},
}
d, err := sheriff.Marshal(&o, communities)
if err != nil {
panic(err)
}
out, _ := json.Marshal(d)
英文:
I developed a library which can help you in this regard: Sheriff
You can annotate your struct fields with special tags and call Sheriff to transform the given struct into a subset of it. After that you can call json.Marshal()
or whatever else you want to marshal into.
Your example would become as simple as:
<!-- language: go -->
type Community struct {
Name string `json:"name" groups:"trending,detail"`
Description string `json:"description" groups:"trending,detail"`
Sources []Source `json:"sources" groups:"detail"`
Popularity int `json:"popularity" groups:"trending,detail"`
FavoriteCount int `json:"favorite_count" groups:"trending,detail"`
Moderators []string `json:"moderators" groups:"detail"`
Children []Community `json:"children" groups:"detail"`
Tracks []Track `json:"tracks" groups:"detail"`
}
communities := []Community{
// communities
}
o := sheriff.Options{
Groups: []string{"trending"},
}
d, err := sheriff.Marshal(&o, communities)
if err != nil {
panic(err)
}
out, _ := json.Marshal(d)
1: https://github.com/liip/sheriff "Sheriff"
答案4
得分: 4
我将为您提供另一种我开发的方法。我认为这种方法更加简洁。唯一的缺点是稍微复杂的对象初始化,但在使用中非常流畅。
主要的观点是,您不是基于原始对象构建JSON视图对象,然后在其中隐藏元素,而是相反,将其作为原始对象的一部分:
type CommunityBase struct {
Name string
Description string
}
type Community struct {
CommunityBase
FavoriteCount int
Moderators []string
}
var comm = Community{CommunityBase{"Name", "Descr"}, 20, []string{"Mod1", "Mod2"}}
json.Marshal(comm)
// {"Name":"Name","Description":"Descr","FavoriteCount":20,"Moderators":["Mod1","Mod2"]}
json.Marshal(comm.CommunityBase)
// {"Name":"Name","Description":"Descr"}
如果您只需要一个视图,或者您的视图逐渐扩展,那就是全部内容。
但是,如果您的视图无法继承,您将不得不使用一种混入的方式,以便可以从中创建一个组合视图:
type ThingBaseMixin struct {
Name string
}
type ThingVisualMixin struct {
Color string
IsRound bool
}
type ThingTactileMixin struct {
IsSoft bool
}
type Thing struct {
ThingBaseMixin
ThingVisualMixin
ThingTactileMixin
Condition string
visualView *ThingVisualView
tactileView *ThingTactileView
}
type ThingVisualView struct {
*ThingBaseMixin
*ThingVisualMixin
}
type ThingTactileView struct {
*ThingBaseMixin
*ThingTactileMixin
}
func main() {
obj := Thing{
ThingBaseMixin: ThingBaseMixin{"Bouncy Ball"},
ThingVisualMixin: ThingVisualMixin{"blue", true},
ThingTactileMixin: ThingTactileMixin{false},
Condition: "Good",
}
obj.visualView = &ThingVisualView{&obj.ThingBaseMixin, &obj.ThingVisualMixin}
obj.tactileView = &ThingTactileView{&obj.ThingBaseMixin, &obj.ThingTactileMixin}
b, _ := json.Marshal(obj)
fmt.Println(string(b))
// {"Name":"Bouncy Ball","Color":"blue","IsRound":true,"IsSoft":false,"Condition":"Good"}
b, _ = json.Marshal(obj.ThingVisualMixin)
fmt.Println(string(b))
// {"Color":"blue","IsRound":true}
b, _ = json.Marshal(obj.visualView)
fmt.Println(string(b))
// {"Name":"Bouncy Ball","Color":"blue","IsRound":true}
b, _ = json.Marshal(obj.tactileView)
fmt.Println(string(b))
// {"Name":"Bouncy Ball","IsSoft":false}
}
在这里,我添加了一个对象的视图,但如果您愿意,您可以在调用Marshal
时创建它:
json.Marshal(ThingVisualView{&obj.ThingBaseMixin, &obj.ThingVisualMixin})
甚至可以在没有预先类型声明的情况下创建它:
json.Marshal(struct{*ThingBaseMixin;*ThingVisualMixin}{&obj.ThingBaseMixin,&obj.ThingVisualMixin})
英文:
I'll present you another approach that I've developed. I think it's much more clean. The only downside is slightly complicated object initialization, but in usage it's very streamlined.
The main point is that you're not basing your JSON-view-object on the original object and then hiding elements in it, but the other way around, making it a part of the original object:
type CommunityBase struct {
Name string
Description string
}
type Community struct {
CommunityBase
FavoriteCount int
Moderators []string
}
var comm = Community{CommunityBase{"Name", "Descr"}, 20, []string{"Mod1","Mod2"}}
json.Marshal(comm)
//{"Name":"Name","Description":"Descr","FavoriteCount":20,"Moderators":["Mod1","Mod2"]}
json.Marshal(comm.CommunityBase)
//{"Name":"Name","Description":"Descr"}
And that's all if you need only one view, or if your views are gradually expanded.
But if your views can't be inherited, you'll have to resort to a kind of mixins, so you can make a combined view from them:
type ThingBaseMixin struct {
Name string
}
type ThingVisualMixin struct {
Color string
IsRound bool
}
type ThingTactileMixin struct {
IsSoft bool
}
type Thing struct {
ThingBaseMixin
ThingVisualMixin
ThingTactileMixin
Condition string
visualView *ThingVisualView
tactileView *ThingTactileView
}
type ThingVisualView struct {
*ThingBaseMixin
*ThingVisualMixin
}
type ThingTactileView struct {
*ThingBaseMixin
*ThingTactileMixin
}
func main() {
obj := Thing {
ThingBaseMixin: ThingBaseMixin{"Bouncy Ball"},
ThingVisualMixin: ThingVisualMixin{"blue", true},
ThingTactileMixin: ThingTactileMixin{false},
Condition: "Good",
}
obj.visualView = &ThingVisualView{&obj.ThingBaseMixin, &obj.ThingVisualMixin}
obj.tactileView = &ThingTactileView{&obj.ThingBaseMixin, &obj.ThingTactileMixin}
b, _ := json.Marshal(obj)
fmt.Println(string(b))
//{"Name":"Bouncy Ball","Color":"blue","IsRound":true,"IsSoft":false,"Condition":"Good"}
b, _ = json.Marshal(obj.ThingVisualMixin)
fmt.Println(string(b))
//{"Color":"blue","IsRound":true}
b, _ = json.Marshal(obj.visualView)
fmt.Println(string(b))
//{"Name":"Bouncy Ball","Color":"blue","IsRound":true}
b, _ = json.Marshal(obj.tactileView)
fmt.Println(string(b))
//{"Name":"Bouncy Ball","IsSoft":false}
}
Here I've added a view into the object, but if you like, you can create it just when calling Marshal
:
json.Marshal(ThingVisualView{&obj.ThingBaseMixin, &obj.ThingVisualMixin})
Or even without a preliminary type declaration:
json.Marshal(struct{*ThingBaseMixin;*ThingVisualMixin}{&obj.ThingBaseMixin,&obj.ThingVisualMixin})
答案5
得分: 0
不确定为什么这不是首选的方法,可能是因为帖子的年代,但据我所知,这是处理此问题的“最佳实践”方式,对于那些在JSON对象中不必存在的字段,可以使用“omitempty”标签。
type Community struct {
Name string `json:"name"`
Description string `json:"description"`
Sources *[]Source `json:"sources,omitempty"`
Popularity int `json:"popularity"`
FavoriteCount int `json:"favorite-count"`
Moderators *[]string `json:"moderators,omitempty"`
Children *[]Community `json:"children,omitempty"`
Tracks *[]Track `json:"tracks,omitempty"`
}
英文:
Not sure why this isn't the preferred method, maybe due to the age of the post, but as far as I know, this is the 'best practice' way to handle this, with 'omitempty' tags for those which don't have to exist in the JSON object.
type Community struct {
Name string `json:"name"`
Description string `json:"description"`
Sources *[]Source `json:"sources,omitempty"`
Popularity int `json:"popularity"`
FavoriteCount int `json:"favorite-count"`
Moderators *[]string `json:"moderators,omitempty"`
Children *[]Community `json:"children,omitempty"`
Tracks *[]Track `json:"tracks,omitempty"`
}
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