英文:
Golang: Convert byte array to big.Int
问题
我正在尝试从存储在字节数组中的模数和指数创建一个RSA公钥。经过一些实验,我得到了以下代码:
func bytes_to_int(b []byte) (acc uint64) {
length := len(b)
if length % 4 != 0 {
extra := (4 - length % 4)
b = append([]byte(strings.Repeat("func bytes_to_int(b []byte) (acc uint64) {
length := len(b)
if length % 4 != 0 {
extra := (4 - length % 4)
b = append([]byte(strings.Repeat("\000", extra)), b...)
length += extra
}
var block uint32
for i := 0; i < length; i += 4 {
block = binary.BigEndian.Uint32(b[i:i+4])
acc = (acc << 32) + uint64(block)
}
return
}
func main() {
fmt.Println(bytes_to_int(data[:128]))
fmt.Println(bytes_to_int(data[128:]))
}
0", extra)), b...)
length += extra
}
var block uint32
for i := 0; i < length; i += 4 {
block = binary.BigEndian.Uint32(b[i:i+4])
acc = (acc << 32) + uint64(block)
}
return
}
func main() {
fmt.Println(bytes_to_int(data[:128]))
fmt.Println(bytes_to_int(data[128:]))
}
这段代码似乎可以工作(尽管我不确定是否有更好的方法)。我的下一步是将其转换为使用math/big来处理更大的数字。我可以看到有一个Lsh函数可以执行左移操作,但是我无法弄清楚如何将Uint32(block)递归地添加到big.Int中。
供参考,我尝试导入的公钥是存储在密钥环(pubring.mix)中的Mixmaster密钥:
http://www.mixmin.net/draft-sassaman-mixmaster-XX.html#key-format
http://pinger.mixmin.net/pubring.mix
英文:
I'm trying to create an RSA Public Key from a Modulus and Exponent stored in a byte array. After some experimentation I've got the following:
func bytes_to_int(b []byte) (acc uint64) {
length := len(b)
if length % 4 != 0 {
extra := (4 - length % 4)
b = append([]byte(strings.Repeat("func bytes_to_int(b []byte) (acc uint64) {
length := len(b)
if length % 4 != 0 {
extra := (4 - length % 4)
b = append([]byte(strings.Repeat("\000", extra)), b...)
length += extra
}
var block uint32
for i := 0; i < length; i += 4 {
block = binary.BigEndian.Uint32(b[i:i+4])
acc = (acc << 32) + uint64(block)
}
return
}
func main() {
fmt.Println(bytes_to_int(data[:128]))
fmt.Println(bytes_to_int(data[128:]))
}
0", extra)), b...)
length += extra
}
var block uint32
for i := 0; i < length; i += 4 {
block = binary.BigEndian.Uint32(b[i:i+4])
acc = (acc << 32) + uint64(block)
}
return
}
func main() {
fmt.Println(bytes_to_int(data[:128]))
fmt.Println(bytes_to_int(data[128:]))
}
This appears to work (although I'm not convinced there isn't a better way). My next step was to convert it to use math/big in order to handle larger numbers. I can see an Lsh function to do the << but can't figure out how to recursively add the Uint32(block) to the big.Int.
For reference, the Public Key I'm attempting to import is a Mixmaster Key stored in a keyring (pubring.mix):
http://www.mixmin.net/draft-sassaman-mixmaster-XX.html#key-format
http://pinger.mixmin.net/pubring.mix
答案1
得分: 21
你想要使用Int.SetBytes方法,通过一个[]byte
切片创建一个big.Int
。
func (z *Int) SetBytes(buf []byte) *Int
SetBytes
方法将buf
解释为大端字节序的无符号整数,并将z
设置为该值,然后返回z
。
根据你提供的文档链接,由于你的密钥是按照大端字节序格式存储的,所以在你的应用程序中使用这个方法应该非常简单。
英文:
You want Int.SetBytes to make a big.int
from a slice of []byte
.
func (z *Int) SetBytes(buf []byte) *Int
SetBytes
interprets buf
as the bytes of a big-endian unsigned integer, sets z
to that value, and returns z
.
This should be quite straightforward to use in your application since your keys are in big-endian format according to the doc you linked.
答案2
得分: 12
import "math/big"
z := new(big.Int)
z.SetBytes(byteSliceHere)
import "math/big"
z := new(big.Int)
z.SetBytes(byteSliceHere)
英文:
import "math/big"
z := new(big.Int)
z.SetBytes(byteSliceHere)
答案3
得分: 4
像Nick提到的那样,你可以使用SetBytes
函数,但要记住输入是base64编码的,所以你需要先解码。
示例:
func Base64ToInt(s string) (*big.Int, error) {
data, err := base64.StdEncoding.DecodeString(s)
if err != nil {
return nil, err
}
i := new(big.Int)
i.SetBytes(data)
return i, nil
}
英文:
Like Nick mentioned, you could use SetBytes
, keep in mind the input is in base64 so you have to decode that first.
func Base64ToInt(s string) (*big.Int, error) {
data, err := base64.StdEncoding.DecodeString(s)
if err != nil {
return nil, err
}
i := new(big.Int)
i.SetBytes(data)
return i, nil
}
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