英文:
Running sh/bash/python scripts with arguments using Go
问题
我已经卡在这个问题上几天了，我试图运行一个基于第一个参数的bash脚本（也许我应该放弃所有希望，哈哈）。
可以假设运行脚本的语法是：
sudo bash script argument 或者由于它具有og+x权限，可以简单地运行 sudo script argument
在Go语言中，我使用以下代码运行它：
package main
import (
"os"
"os/exec"
"fmt"
)
func main() {
c := exec.Command("/bin/bash", "script " + argument)
if err := c.Run(); err != nil {
fmt.Println("Error: ", err)
}
os.Exit(0)
}
我完全没有运气，我还尝试了很多其他变体...
exec.Command("/bin/sh", "-c", "sudo script", argument)
exec.Command("/bin/sh", "-c", "sudo script " + argument)（我的第一次尝试）
exec.Command("/bin/bash", "-c", "sudo script" + argument)
exec.Command("/bin/bash", "sudo script", argument)
exec.Command("/bin/bash sudo script" + argument)
大多数情况下，我遇到了/bin/bash sudo ect没有这样的文件或目录，或者Error: exit status 1。我甚至写了一个Python包装器，寻找一个参数并使用subprocess执行bash脚本，以排除脚本路径未定义的可能性，我尝试了上述所有方法，而不是脚本名称。
为了保留我剩下的头发，我在这里做错了什么？如何更好地诊断这个问题，以便我可以获得更多信息，而不仅仅是退出状态1？
英文:
I've been stuck on this one a few days, I'm trying to run a bash script which runs off of the first argument (maybe I should give up all hope, haha)
Syntax for running the script can be assumed to be:
sudo bash script argument or since it has og+x it can be ran as just sudo script argument
In go I'm running it using the following:
package main
import (
"os"
"os/exec"
"fmt"
)
func main() {
c := exec.Command("/bin/bash", "script " + argument)
if err := c.Run(); err != nil {
fmt.Println("Error: ", err)
}
os.Exit(0)
}
I have had absolutely no luck, I've tried loads of other variations as well for this...
exec.Command("/bin/sh", "-c", "sudo script", argument)
exec.Command("/bin/sh", "-c", "sudo script " + argument) (my first try)
exec.Command("/bin/bash", "-c", "sudo script" + argument)
exec.Command("/bin/bash", "sudo script", argument)
exec.Command("/bin/bash sudo script" + argument)
Most of these I am met with '/bin/bash sudo ect' no such file or directory, or Error: exit status 1 I have even gone as far as to write a Python wrapper looking for an argument and executing the bash script with subprocess. To rule out the path to the script not being defined I have tried all of the above with a direct route to the script rather than script name.
For the sake of my remaining hair, what am I doing wrong here? How can I better diagnose this problem so that I can get more information rather than exit status 1?
答案1
得分: 4
你根本不需要调用bash/sh，只需单独传递每个参数，而且要获取错误信息，你需要捕获命令的stderr。下面是一个可行的示例：
func main() {
c := exec.Command("sudo", "ls", "/tmp")
stderr := &bytes.Buffer{}
stdout := &bytes.Buffer{}
c.Stderr = stderr
c.Stdout = stdout
if err := c.Run(); err != nil {
fmt.Println("错误: ", err, "|", stderr.String())
} else {
fmt.Println(stdout.String())
}
os.Exit(0)
}
这段代码会执行sudo ls /tmp命令，并将stdout和stderr分别存储在stdout和stderr变量中。如果命令执行出错，将打印错误信息和stderr的内容；否则，将打印stdout的内容。最后，使用os.Exit(0)退出程序。
英文:
You don't need to call bash/sh at all, simply pass each argument alone, also to get the error you have to capture the command's stderr, here's a working example:
func main() {
c := exec.Command("sudo", "ls", "/tmp")
stderr := &bytes.Buffer{}
stdout := &bytes.Buffer{}
c.Stderr = stderr
c.Stdout = stdout
if err := c.Run(); err != nil {
fmt.Println("Error: ", err, "|", stderr.String())
} else {
fmt.Println(stdout.String())
}
os.Exit(0)
}
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