如何展平嵌套的JSON数据结构

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英文:

How to flatten nested JSON

问题

尝试将嵌套的 JSON 响应从两层深度展平为一层。您怀疑需要编写一个自定义的 UnmarshalJSON 函数,但是对于如何编写这样的函数以及对 Go 语言不熟悉。

建议如下:

您可以使用匿名结构体来展平嵌套的 JSON 响应。首先,将 Social 结构体中的 Facebook 字段更改为匿名结构体。然后,使用 json:"字段名" 标签将嵌套的字段映射到相应的字段名。这样,您就可以直接访问嵌套字段的值。

以下是修改后的代码示例:

package main

import (
	"encoding/json"
	"fmt"
)

type Social struct {
	GooglePlusPlusOnes  uint32 `json:"GooglePlusOne"`
	TwitterTweets       uint32 `json:"Twitter"`
	LinkedinShares      uint32 `json:"LinkedIn"`
	PinterestPins       uint32 `json:"Pinterest"`
	StumbleuponStumbles uint32 `json:"StumbleUpon"`
	DeliciousBookmarks  uint32 `json:"Delicious"`
	Facebook            `json:"Facebook"`
}

type Facebook struct {
	FacebookLikes    uint32 `json:"like_count"`
	FacebookShares   uint32 `json:"share_count"`
	FacebookComments uint32 `json:"comment_count"`
	FacebookTotal    uint32 `json:"total_count"`
}

func main() {
	var jsonBlob = []byte(`[
		{"StumbleUpon":0,"Reddit":0,"Facebook":{"commentsbox_count":4691,"click_count":0,"total_count":298686,"comment_count":38955,"like_count":82902,"share_count":176829},"Delicious":0,"GooglePlusOne":275234,"Buzz":0,"Twitter":7346788,"Diggs":0,"Pinterest":40982,"LinkedIn":0}
	]`)

	var social []Social
	err := json.Unmarshal(jsonBlob, &social)
	if err != nil {
		fmt.Println("error:", err)
	}
	fmt.Printf("%+v", social)
}

这样,您就可以直接访问 Social 结构体中的 Facebook 字段,而不需要通过嵌套的结构体来访问。

希望这可以帮助到您!

英文:

Trying to flatten a nested json response from 2 levels deep down to 1.

Here is my working code on Go Playground: http://play.golang.org/p/kHAYuZUTko

I want to end up with:

type Social struct {
	GooglePlusPlusOnes  uint32 `Social:"GooglePlusOne"`
	TwitterTweets       uint32 `json:"Twitter"`
	LinkedinShares      uint32 `json:"LinkedIn"`
	PinterestPins       uint32 `json:"Pinterest"`
	StumbleuponStumbles uint32 `json:"StumbleUpon"`
	DeliciousBookmarks  uint32 `json:"Delicious"`
	FacebookLikes       uint32 `json:"??some_magical_nested_address??"`
	FacebookShares      uint32 `json:"??some_magical_nested_address??"`
	FacebookComments    uint32 `json:"??some_magical_nested_address??"`
	FacebookTotal       uint32 `json:"??some_magical_nested_address??"`
}

...instead of a Social type containing a nested Facebook type (seen in the code below).

I suspect I'll need to do a custom UnmarshalJSON function, but I don't know how those work and I'm new to Go.

Suggestions?


Here is the code from the Go Playground link above:

package main

import (
	"encoding/json"
	"fmt"
)

type Social struct {
	GooglePlusPlusOnes  uint32 `json:"GooglePlusOne"`
	TwitterTweets       uint32 `json:"Twitter"`
	LinkedinShares      uint32 `json:"LinkedIn"`
	PinterestPins       uint32 `json:"Pinterest"`
	StumbleuponStumbles uint32 `json:"StumbleUpon"`
	DeliciousBookmarks  uint32 `json:"Delicious"`
	Facebook            Facebook
}

type Facebook struct {
	FacebookLikes    uint32 `json:"like_count"`
	FacebookShares   uint32 `json:"share_count"`
	FacebookComments uint32 `json:"comment_count"`
	FacebookTotal    uint32 `json:"total_count"`
}

func main() {
	var jsonBlob = []byte(`[
		{"StumbleUpon":0,"Reddit":0,"Facebook":{"commentsbox_count":4691,"click_count":0,"total_count":298686,"comment_count":38955,"like_count":82902,"share_count":176829},"Delicious":0,"GooglePlusOne":275234,"Buzz":0,"Twitter":7346788,"Diggs":0,"Pinterest":40982,"LinkedIn":0}
	]`)

	var social []Social
	err := json.Unmarshal(jsonBlob, &social)
	if err != nil {
		fmt.Println("error:", err)
	}
	fmt.Printf("%+v", social)
}

答案1

得分: 9

如果你只使用地图,这个函数将会很有用。

// Flatten函数接受一个地图,并返回一个新的地图,其中嵌套的地图被替换为点分隔的键。
func Flatten(m map[string]interface{}) map[string]interface{} {
o := make(map[string]interface{})
for k, v := range m {
switch child := v.(type) {
case map[string]interface{}:
nm := Flatten(child)
for nk, nv := range nm {
o[k+"."+nk] = nv
}
default:
o[k] = v
}
}
return o
}

英文:

If you are only using maps this function will be useful.

// Flatten takes a map and returns a new one where nested maps are replaced
// by dot-delimited keys.
func Flatten(m map[string]interface{}) map[string]interface{} {
    o := make(map[string]interface{})
    for k, v := range m {
            switch child := v.(type) {
            case map[string]interface{}:
                    nm := Flatten(child)
                    for nk, nv := range nm {
                            o[k+"."+nk] = nv
                    }
            default:
                    o[k] = v
            }
    }
    return o
}

答案2

得分: 7

你可以简单地将Facebook结构体嵌入进去:

type Social struct {
    .....
    Facebook            `json:"Facebook"`
}

然后可以这样访问它:

social.FacebookLikes

工作示例:http://play.golang.org/p/xThhX_92Sg

英文:

You can simply embed the Facebook struct:

type Social struct {
	.....
	Facebook            `json:"Facebook"`
}

Then access it like:

social.FacebookLikes

Working example: http://play.golang.org/p/xThhX_92Sg

huangapple
  • 本文由 发表于 2014年7月9日 06:35:07
  • 转载请务必保留本文链接:https://go.coder-hub.com/24642575.html
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