Find the real caller in method call

I have a struct like this:

type Parent struct {
    example string
}
func (p *Parent) GetMyAttr() {
	typ := reflect.TypeOf(p).Elem()
	for i := 0; i < typ.NumField(); i++ {
		p := typ.Field(i)
		if !p.Anonymous {
			fmt.Println(p.Name, ":", p.Type)
		}
	}
}

And if I have another struct like this:

type Child struct {
	Parent
	another string
}

call GetTypeOfMe() in child like this

ch := Child{Parent{"example"},"another"}
ch.GetMyAttr()

is always return example : string .
Is this possible to get Child struct in Parent struct with reflection?

Full code is here http://play.golang.org/p/ej4Xh_V2J1

No, since you operate on a *Parent, not a *Child.
This would "work" (play.golang)

func (p *Child) GetMyAttr() {...

would output:

Parent : main.Parent
another : string

A Parent doesn't know about the struct which might embed it, so the reflection operates only on Parent struct.

You see a similar issue with "Go Reflection with Embedding", which uses interface{} to get to all the struct passed in parameter.

It doesn't work like this, reflect.TypeOf(p).Elem() will always return Parent you have 2 options, either implement GetMyAttr for each child or use a generic function like :

func GetAttr(i interface{}) {
	typ := reflect.Indirect(reflect.ValueOf(i)).Type()
	fmt.Println(typ)
	for i := 0; i < typ.NumField(); i++ {
		p := typ.Field(i)
		fmt.Println(p.Name, ":", p.Type)
	}
}