英文:
Is it possible to "return" a function from another function?
问题
由于冗长的错误处理语法，我创建了一个名为check的函数，作为一个“全局”错误处理程序。如果我想要抛出错误而不是记录日志，我只需要修改check函数。问题是，现在我想要简单地return，这样其他的Go协程在其中一个出现错误时仍然可以运行。所以问题是：我该如何做到这一点？是否可能？
func main() {
for k, v := range foo {
go func() {
err = doSomething()
check("this one failed", err)
}()
}
}
func check(errMsg string, err error) {
if err != nil {
return // 在这里返回而不是使用 log.Fatalf
}
}
然而，现在我发现如果有任何错误，我需要返回匿名函数而不是退出（使用log.Fatal），所以我想知道是否可能返回匿名函数。
英文:
Due the verbose error handling syntax I've created a function check as below which acts as a "global" error handler. If I want to panic instead to log I change only the check function. The issue is that now I want to simply return so that the other go routines can still run if one has an error. So the question is: How can I do that ? Is it possible?
func main() {
for k, v := range foo {
go func() {
err = doSomething()
check("this one failed", err)
}()
}
}
func check(errMsg string, err error) {
if err != nil {
log.Fatalf(errMsg, err)
}
}
However now I've found that I need return the anonymous function if there is any error rather than exit ( log.Fatal ) so I'm wondering if it's possible to return the anyonymou
答案1
得分: 2
你可以让你的check函数返回一个bool值：
func checkIfFailed(errMsg string, err error) bool {
if err != nil {
log.Printf(errMsg, err)
return true
}
return false
}
这样，你仍然可以调用你的check函数（并在其中进行各种检查），同时可以从匿名函数中提前返回：
err = doSomething()
if checkIfFailed("this one failed", err) {
return
}
英文:
You could make your check function returns a bool:
func checkIfFailed(errMsg string, err error) bool {
if err != nil {
log.Printf(errMsg, err)
return true
}
return false
}
That way, you can still call your check (and do all kind of checks in it), while returning early from the anonymous function:
err = doSomething()
if checkIfFailed("this one failed", err) {
return
}
答案2
得分: 0
没有一种语言特性可以使父函数在简单函数调用的情况下自动返回。
但是，有一种方法可以导致当前 goroutine 退出，这可能是你想要的：runtime.Goexit。请注意，这与调用 os.Exit 具有类似的破坏性潜力，因此在由其他包或其他不相关代码创建的 goroutine 上调用它将是不好的。
英文:
There isn't a language feature that allows you to cause the parent function to automatically return in response to a simple function call.
However, there is a way to cause the current goroutine to exit, which might be what you are after: runtime.Goexit. Note that this has similar disruptive potential to calling os.Exit, so it would be bad to call it in the context of goroutines created by other packages or other unrelated code.
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