英文:
Golang (beginner): Avoiding duplicate functions to deal with strings or ints
问题
我今天开始学习Go语言，所以这可能是一个愚蠢的问题。我习惯了PHP，其中我不需要声明变量类型。
我正在将一些常用的PHP函数转换为Go函数。我有一个函数，它将数组转换为哈希表，以便以后可以快速查找（比通过迭代数组查找值是否存在要快得多，而是将值作为键）。
在我看来，我需要创建两个单独的函数，一个用于字符串，一个用于整数（uint，因为我不需要有符号整数）。为了方便维护，我希望有一个函数可以接受string或uint，并返回相同的类型，即它可以处理并返回我最初传递给函数的类型。
目前我有这样的代码：
// Array2Map_string 将字符串数组转换为哈希表：word=>false
func Array2Map_string(a []string) map[string]bool {
mc := make(map[string]bool)
for _,tok := range a {
mc[tok]=false
}
return mc
}
// Array2Map_int 将整数数组转换为哈希表：int=>false
func Array2Map_int(a []uint) map[uint]bool {
mc := make(map[uint]bool)
for _,tok := range a {
mc[tok]=false
}
return mc
}
我想要的是一个单一的函数，如果我将一个字符串数组传递给该函数，它将创建并返回一个基于字符串的哈希表，如果我将一个整数数组传递给该函数，它将创建并返回一个基于整数的哈希表。例如：
// Array2Map 将数组转换为哈希表，键为whatever类型
func Array2Map(a []whatever) map[whatever]bool {
mc := make(map[whatever]bool)
for _,tok := range a {
mc[tok]=false
}
return mc
}
这种做法可行吗？
英文:
I've started learning Go today, so this may be a silly question. I'm used to PHP whereby I don't have to declare variable types.
I'm currently converting some of my commonly used PHP functions into Go functions. I have a function which converts an array into a hashtable for fast lookups later on (much faster than iterating through the array to see if a value exists, instead the values become keys.)
It seems to me that I have to create two separate functions, one for strings and one for integers (uint as I don't need signed integers). For the sake of maintenance I would prefer to have one function that can accept either string or uint and return the same, i.e. it works in and returns whatever I originally pass to the function.
Currently I have this:
// Array2Map_string makes a map out of an array of strings: word=>false
func Array2Map_string(a []string) map[string]bool {
mc := make(map[string]bool)
for _,tok := range a {
mc[tok]=false
}
return mc
}
// Array2Map_int makes a map out of an array of integers: int=>false
func Array2Map_int(a []uint) map[uint]bool {
mc := make(map[uint]bool)
for _,tok := range a {
mc[tok]=false
}
return mc
}
What I would like is to have a single function that will create and return a string based hashtable if I send a string array to the function, or a uint based hashtable if I send a uint array to the function. Example:
// Array2Map makes a map out of an array of strings whereby the key is
func Array2Map(a []whatever) map[whatever]bool {
mc := make(map[whatever]bool)
for _,tok := range a {
mc[tok]=false
}
return mc
}
Is that possible?
答案1
得分: 3
泛型在Go语言中尚不存在（尽管有很多关于它的讨论）。目前来说，我认为你当前的方向是你唯一的选择。
英文:
Generics don't exist in Go yet (although there is a lot of discussion about it. For now, I think your current direction is your only option.
1: http://www.reddit.com/r/golang/comments/1x7txi/why_generics/ "discussion"
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